A ) The displacement:
d = v o t - (gt²) / 2 =
= 19.6 m/s × 1 s - ( 9.8 m/s² x 1 s² ) / 2 =
= 19.6 m - 4.9 m = 14.7 m
b ) v = v o - g t
0 = 19.6 m/s - 9.8 t ( when the ball is at the highest point )
9.8 t = 19.6
t = 19.6 : 9.8
t = 2 s
h = v o t - (gt²)/2 = 19.6 x 2 - ( 9.8 x 4 ) / 2 = 39.2 - 19.6
h = 19.6 m
c ) h = gt² / 2
19.6 = 9.8 t²/2
9.8 t² = 39.2
t² = 39.2 : 9.8
t² = 4
t 2 = 2 s ( and we know that t 1 = 2 s )
t = t 1 + t 2 = 2 s + 2 s = 4 s
The arrow of acceleration would have to be the one that is slightly at an angle and to the right if I am correct, the angle of collision with the side, would cause the puck's acceleration to be not quite directly forward nor directly sideways.
Work is done when a spring is extended or compressed . Elastic potential energy is stored in the spring hope that helpss.
Answer:
Explanation:
Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:
Where:
- Angular speed, measured in radians per second.
- Radius of rotation, measured in meters.
The angular speed is first determined:
Where 
is the angular speed, measured in revolutions per minute.
If 
, the angular speed measured in radians per second is:
Now, if 
and 
, the resultant acceleration is then:
If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:
