The final velocity of the car is +1.5 m/s.
Explanation:
We have to divide the problem into two parts.
In the first part, the car starts from rest and accelerates for 5.0 s. We can find the final velocity of the car after this first part using the suvat equation:
where
v is the final velocity
u = 0 is the initial velocity
is the acceleration
t = 5.0 s is the time
Substituting,
In the second part, the brakes are applied, so the car decelerates for 3.0 s, and the final velocity is given by
where
v' is the final velocity
v = 7.5 m/s is the velocity at the beginning of this part
is the deceleration
t = 3.0 s is the time
Substituting,
So, the final velocity is +1.5 m/s.
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Answer:
a = 603.59 m/s^2
Explanation:
from the data given . the rate of change in magnetic field is as follow
from the faraday's law of induction , the expression for the induced emf in region of radius r as follow
electric field at point P_1 as follow
from newton 2nd law of motion, the acceleration of proton is
F = ma
qE = ma
a = 603.59 m/s^2