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Olin [163]
3 years ago
11

A box of groceries requires 5.0 newtons of force to lift it up 1.0 meter. How much work is done?

Physics
2 answers:
Triss [41]3 years ago
8 0
5.0j as we know that work is derived as force into displacement so 5*1=5si force will be 5.0j
professor190 [17]3 years ago
6 0
Work is done when a force that is applied to an object moves that object. Thework is calculated by multiplying the force by the amount of movement of an object. We do as follows:

W = Fd
W = 5 x 1.0
W = 5 J<span> <----OPTION D</span>
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Answer:

207.4 N

Explanation:

The torque \tau  on a body is

\tau = r* F  where r is the radius vector from the point of rotation to the point at which force F is applied.

The product of r and F is equal to the product of magnitude of r and F multiplied by the sine of angle between both vectors.

Therefore, torque is also given by

\tau = rF\sin \theta

Where \theta is the angle between r and F.

Use the expression of torque.

Substitute L for r in the equation \tau = rF\sin \theta

\tau = LF\sin \theta

Where L is the length of the wrench.

Making F the subject

F = \frac{\tau }{{L\sin \theta }}

Force required to pull the wrench is given as,

F = \frac{\tau }{{L\sin \theta }}

Substitute 47{\rm{ N}} \cdot {\rm{m}}  for \tau, 25 cm for L, and 115o for \theta  

\begin{array}{c}\\F = \frac{{47{\rm{ N}} \cdot {\rm{m}}}}{{\left( {25{\rm{ cm}}} \right)\sin {{115}^{\rm{o}}}}}\left( {\frac{{1{\rm{ cm}}}}{{{{10}^{ - 2}}{\rm{ m}}}}} \right)\\\\ = 207.435{\rm{ N}}\\\\ \approx 207.4{\rm{ N}}\\\end{array}  

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