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Deffense [45]
3 years ago
6

Which salt is produced when NH4OH Reacts with HNO3

Chemistry
2 answers:
borishaifa [10]3 years ago
5 0

Explanation:

When an acid reacts with a base then it results in the formation of salt and water.

HNO_{3} is an acid and NH_{4}OH is a base thus, when we dissolve ammonium hydroxide in nitric acid then it results in the formation of ammonium nitrate and water.

The reaction is as follows.

 NH_{4}OH + HNO_{3} \rightarrow NH_{4}NO_{3} + H_{2}O

Hence, there will be formation of ammonium nitrate (NH_{4}NO_{3}) salt.


m_a_m_a [10]3 years ago
3 0
This would be an example of a double replacement type of reaction, the salt that is produced would be with the ions of ammonium and nitrate, NO3^-.

The salt is (NH4)NO3.
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Warm and wet climate
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Where does photosynthesis occur in a plant cell? In what part of a plant cell does photosynthesis occur?
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Explanation:

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Phosphorus-32 (32P) is an isotope that is commonly used for medical and biological research. Phosphorus-32 has a half-life of 14
Pachacha [2.7K]

The activity of the sample when it was shipped from the manufacturer is 4.54 mCi

<h3>How to determine the number of half-lives that has elapsed </h3>

From the question given above, the following data were obtained:

  • Time (t) = 48 hours
  • Half-life (t½) = 14.28 days = 14.28 × 24 = 342.72 hours
  • Number of half-lives (n) =?

n = t / t½

n = 48 / 342.72

n = 0.14

<h3>How to determine the activity of the sample during shipping </h3>
  • Number of half-lives (n) = 0.14
  • Original activity (N₀) = 5.0 mCi
  • Activity remaining (N) =?

N = N₀ / 2ⁿ

N = 5 / 2^0.14

N = 4.54 mCi

Thus, the activity of the sample during shipping is 4.54 mCi

Learn more about half life:

brainly.com/question/2674699

5 0
3 years ago
How many grams of HNO3 are produced when 59.0 g of NO2 completely reacts?
Anettt [7]

Answer:

53.7 grams of HNO3 will be produced

Explanation:

Step 1: Data given

Mass of NO2 = 59.0 grams

Molar mass NO2 = 46.0 g/mol

Step 2: The balanced equation

3NO2 + H2O→ 2HNO3 + NO

Step 3: Calculate moles NO2

Moles NO2 = 59.0 grams / 46.0 g/mol

Moles NO2 = 1.28 moles

Step 4: Calculate moles HNO3

For 3 moles NO2 we need 1 mol H2O to produce 2 moles HNO3 and 1 mol NO

For 1.28 moles NO2 we'll have 2/3 * 1.28 =0.853 moles HNO3

Step 7: Calculate mass HNO3

Mass HNO3 = 0.853 moles * 63.01 g/mol

Mass HNO3 = 53.7 grams

53.7 grams of HNO3 will be produced

3 0
3 years ago
100.mL of a .795 M solution of KBr is diluted to 500.mL. what is the new concentration of the solution?
kap26 [50]

Answer:

0.159 M

Explanation:

convert from mL to L then use the equation:

M1V1 = M2V2

rearrange to find M2

\frac{M1V1}{V2} = M2

\frac{(0.795 M)(0.100 L)}{0.500 L} = 0.159 M

4 0
3 years ago
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