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3 years ago

Which salt is produced when NH4OH Reacts with HNO3

Chemistry

2 answers:

borishaifa [10]3 years ago

5 0

Explanation:

When an acid reacts with a base then it results in the formation of salt and water.

$HNO_{3}$ is an acid and $NH_{4}OH$ is a base thus, when we dissolve ammonium hydroxide in nitric acid then it results in the formation of ammonium nitrate and water.

The reaction is as follows.

$NH_{4}OH + HNO_{3} \rightarrow NH_{4}NO_{3} + H_{2}O$

Hence, there will be formation of ammonium nitrate $(NH_{4}NO_{3})$ salt.

m_a_m_a [10]3 years ago

3 0

This would be an example of a double replacement type of reaction, the salt that is produced would be with the ions of ammonium and nitrate, NO3^-.

The salt is (NH4)NO3.

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For example, water. In its liquid state we drink it , in its solid state (ice ) we use it to make our drinks colder or t numbs pain when wrapped in cloth and it’s gas state ( water vapour) we steam vegetables. In conclusion many different properties of matter are used for various purposes

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3 years ago

How much heat does a 100. g sample of copper absorb when its temperature increases by 30.0°C? The specific heat of copper is 0.3

erica [24]

Answer:

$\boxed {\boxed {\sf B. \ 1170 \ Joules }}$

Explanation:

We are asked to find how much heat a sample of copper absorbs when the temperature is increased.

Since we know the mass, temperature increase, and specific heat capacity, we can use the following formula to calculate heat.

$q= mc \Delta T$

The mass of the copper sample is 100 grams, the temperature is changed or increased by 30.0 degrees Celsius, and the specific heat of copper is 0.39 Joules per gram degrees Celsius.

m= 100 g
c= 0.39 J/g °C
ΔT= 30.0 °C

Substitute the values into the formula.

$q= (100 \ g )(0.39 \ J/g \textdegree C ) (30.0 \textdegree C )$

Multiply the first two values. Note that the units of grams cancel.

$q= 39 \ J/ \textdegree C (30.0 \textdegree C )$

Multiply again, this time the units of degrees Celsius cancel.

$q= 1170 \ J$

The copper sample absorbs <u>1170 Joules</u> of heat and <u>Choice B </u>is correct.

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3 years ago

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Answer:

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3 years ago

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Answer:

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3 years ago

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Varvara68 [4.7K]

Answer:

Yes.

Explanation:

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The first calculated value for the concentration of the compound will be regarded as rough value, while the second and the third will be regarded as the first and second values respectively.

In this case, the third value for the concentration of HCl will be calculated to for confirmation of other value, that is to be finally sure of its concentration.

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3 years ago

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