Y=15 x=60
•1/3 •1/3
y=5 x=45
Use the formula for volume. V = lwh. Plug in the numbers for length, width, and height. Now we have V = 4.0 x 2.0 x 1.0, which is 8.0. So the volume of the block is 8.0 cm.
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K₃PO₄ → 3K⁺ + PO₄³⁻
PO₄³⁻ + H₂O ⇄ HPO₄²⁻ + OH⁻
HPO₄²⁻ + H₂O ⇄ H₂PO₄⁻ + OH⁻
H₂PO₄⁻ + H₂O ⇄ H₃PO₄ + OH⁻
K⁺, PO₄³⁻, HPO₄²⁻, H₂PO₄⁻, OH⁻
Brownie mix is a heterogeneous mixture:)
The molecular problem for aluminum oxide is Al2O3 Atomic mass of Al = 26.982 Atomic mass of O = 16 From the problem, 1 mole of AL2O3 contains: 2 g-atom of Al or 2 x 26.982 = 53.964 g 3 g-atom of O or 3 x 16 = 48 g the mass of 1 mole of Al2O3 is equal to 53.964 + 48 = 101.964 g