A chemistry student was asked to calculate the number of moles of iron required to react with 1.20 mol of oxygen to produce iron
(iii) oxide. his calculation is shown below :
1.20 mol O2 x 1 mol fe / 1 mol O2 = 1.20 mol Fe
Is the student correct? Use evidence to support your answer.
1.20 mol O2 x 1 mol fe / 1 mol O2 = 1.20 mol Fe
Is the student correct? Use evidence to support your answer.
1 answer:
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2.168 L of air will leave the container as it warms
<h3>Further explanation</h3>Given
V₁=2.05 L
T₁ = 5 + 273 = 278 K
T₂ = 21 + 273 = 294 K
Required
Volume of air
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
Input the value :
V₂=(V₁.T₂)/T₁
V₂=(2.05 x 294)/278
V₂=2.168 L
<u>Answer:</u> The mass of solid NaOH required is 80 g
<u>Explanation:</u>
Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:
where,
n = acidity for bases = 1 (For NaOH)
Molar mass of NaOH = 40 g/mol
Putting values in above equation, we get:
Normality is defined as the umber of gram equivalents dissolved per liter of the solution.
Mathematically,
Or,
......(1)
We are given:
Given mass of NaOH = ?
Equivalent mass of NaOH = 40 g/eq
Volume of solution = 400 mL
Normality of solution = 5 eq/L
Putting values in equation 1, we get:
Hence, the mass of solid NaOH required is 80 g