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2 years ago

Chemical and physical properties of the seaborgium element

Chemistry

1 answer:

natka813 [3]2 years ago

6 0

Answer:

Seaborgium is an artificially produced radioactive chemical element, it's appearance is unknown, it probably has a silvery white or metallic gray colour. The most stable isotope Sg 271 has an half life of 2.4 minutes.

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Consider the balanced reaction: 4Ga(s) + 3O2(g)⟶ 2Ga2O3(s)

Paha777 [63]

First we need to find the number of moles that 43.9g of gallium metal is. We can do this by finding the molar weight of gallium and cross-multiplying to cancel out units:

$\frac{1mole}{69.723g}*\frac{43.9g}{1}=0.63mol_{Ga}$

So we are dealing with 0.63 moles of gallium metal.

We can take from the balanced equation that 4 moles of gallium metal will react completely with 3 moles of oxygen gas. We can take this ratio and make a proportion to find the amount of oxygen gas, in moles, that will react completely with 0.63 moles of gallium metal:

$\frac{4moles_{Ga}}{3moles_{O_{2}}} =\frac{0.63moles_{Ga}}{xmoles_{O_{2}}}$

Cross multiply and solve for x:

$4x=1.89$

$x=0.47moles_{O{2}}$

So now we know that 0.47 moles of oxygen gas will react with 43.9g of gallium metal.

5 0

3 years ago

？？？？？？？？？？？hahshshhshshsh

vazorg [7]

Answer:

structure

Explanation:

7 0

3 years ago

Explain in brief how some bacteria cause tooth cavities

soldier1979 [14.2K]

Answer:

because some bacteria change the ph of the teeth and leads to tooth cavitiew

7 0

3 years ago

Read 2 more answers

6. If concentrations measured in moles per liter, and time in seconds, what are the units of the rate constant for (a) a first o

kaheart [24]

Answer:

(a) a first order reaction = s^-1.

(b) a second-order reaction = L(mol·s)

Explanation:

Okay, this question is a question that has to do with kinetics that is how reaction occurs.

So, the RATE LAW is one of the concept that is being used in determining conditions of chemical reactions. The relationship between the the reactants molarity and the reaction rate is known as rate law. That is to say;

Rate law = K × Molarity.

So, In this question we are given that the concentrations measured in moles per liter, and time in seconds.

The FIRST ORDER REACTION has its unit for rate constant as per seconds(s^-1).

That is from; Rate law = k

Molarity/s = k × Molarity.

k = s^-1

(b) a second-order reaction;

Rate law= k × (molarity)^2.

Molarity/s = k × (Molarity)^2.

k = L(mol·s)

Same thing applies.

5 0

3 years ago

Read 2 more answers

For the following reaction, 15.4 grams of chlorine gas are allowed to react with 49.6 grams of sodium iodide. chlorine (g) sodiu

mariarad [96]

Answer:

19.3 g of NaCl can be produced

Explanation:

We state the reaction:

Cl₂ (g) + 2NaI (s) → 2NaCl (s) + I₂ (s)

We need to determine limiting reagent:

15.4 g . 1mol /70.9g = 0.217 moles of chlorine

49.6 g . 1mol / 149.89g = 0.331 moles of NaI

Ratio is 1:2. 1 mol of chlorine reacts to 2 moles of NaI

0.217 moles may react to (0.217 . 2)/1 = 0.434 moles of NaI

It is ok to say the NaI is the limting reactant because we need 0.434 moles of it and we only have 0.331.

Ratio is 2:2.

0.331 moles of NaI can produce 0.331 moles of NaCl

We convert mass to moles: 0.331 mol . 58.45g /mol = 19.3 g

3 0

3 years ago