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stepan [7]
3 years ago
10

Are all mutation effects the same? Provide examples?

Chemistry
2 answers:
GREYUIT [131]3 years ago
8 0

Answer: Effects of Mutations

A single mutation can have a large effect, but in many cases, evolutionary change is based on the accumulation of many mutations with small effects. Mutational effects can be beneficial, harmful, or neutral, depending on their context or location. Most non-neutral mutations are deleterious.

Other common mutation examples in humans are Angelman syndrome, Canavan disease, color blindness, cystic fibrosis, Down syndrome, Duchenne muscular dystrophy, haemochromatosis, haemophilia, Klinefelter syndrome, phenylketonuria, Prader–Willi syndrome, Tay–Sachs disease, and Turner syndrome

PLZZ GIVE ME BRAINLIEST

san4es73 [151]3 years ago
3 0

A single mutation can have a large effect, but in many cases, evolutionary change is based on the accumulation of many mutations with small effects. Mutational effects can be beneficial, harmful, or neutral, depending on their context or location. Most non-neutral mutations are deleterious.

Other common mutation examples in humans are Angelman syndrome, Canavan disease, color blindness, cystic fibrosis, Down syndrome, Duchenne muscular dystrophy, haemochromatosis, haemophilia, Klinefelter syndrome, phenylketonuria, Prader–Willi synExplanation:

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professor190 [17]

Answer:

No

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4 years ago
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4 years ago
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Calculate the number of moles in 7.41 X 1017 atoms Ag.
jolli1 [7]

Answer:

1.23x10^-6 mole

Explanation:

A clear understanding of Avogadro's hypothesis proved that 1mole of any substance contains 6.02x10^23 atoms. This indicates that 1mole of Ag contains 6.02x10^23 atoms.

Now, 1f 1mole of Ag contains 6.02x10^23 atoms, then Xmol of Ag will contain 7.41x10^17 atoms i.e

Xmol of Ag = 7.41x10^17/6.02x10^23 = 1.23x10^-6 mole

4 0
3 years ago
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5 0
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How many C-13 atoms are present, on average, in a 1.6000×104-atom sample of carbon?
san4es73 [151]
I don't know why I am answering this question but assuming C-13 has a natural abundance of 1.07%:

(1.6000x10^4)(0.0107) = 171.2 = 171 atoms of C-13
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3 years ago
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