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stepan [7]
2 years ago
10

Are all mutation effects the same? Provide examples?

Chemistry
2 answers:
GREYUIT [131]2 years ago
8 0

Answer: Effects of Mutations

A single mutation can have a large effect, but in many cases, evolutionary change is based on the accumulation of many mutations with small effects. Mutational effects can be beneficial, harmful, or neutral, depending on their context or location. Most non-neutral mutations are deleterious.

Other common mutation examples in humans are Angelman syndrome, Canavan disease, color blindness, cystic fibrosis, Down syndrome, Duchenne muscular dystrophy, haemochromatosis, haemophilia, Klinefelter syndrome, phenylketonuria, Prader–Willi syndrome, Tay–Sachs disease, and Turner syndrome

PLZZ GIVE ME BRAINLIEST

san4es73 [151]2 years ago
3 0

A single mutation can have a large effect, but in many cases, evolutionary change is based on the accumulation of many mutations with small effects. Mutational effects can be beneficial, harmful, or neutral, depending on their context or location. Most non-neutral mutations are deleterious.

Other common mutation examples in humans are Angelman syndrome, Canavan disease, color blindness, cystic fibrosis, Down syndrome, Duchenne muscular dystrophy, haemochromatosis, haemophilia, Klinefelter syndrome, phenylketonuria, Prader–Willi synExplanation:

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A mixture of 10 cm3 of methane and 10 cm3 of ethane was sparked with an excess of oxygen. After cooling to room temperature, thr
Tpy6a [65]
In the combustion process using excess oxygen, each mole of methane results to 1 mole of co2 while ethane produces 2 moles of Co2. Under same conditions, these can be translated to volume. Hence the total volume absorbed is 10 cm3 + 20 cm3 = 30 cm3.
5 0
3 years ago
Automotive air bags inflate when sodium azide, NaN3, decomposes explosively to its constituent elements. How many moles of nitro
attashe74 [19]

Answer:

2.29 g of N2

Explanation:

We have to start with the <u>chemical reaction</u>:

NaN_3~->~Na~+~N_2

The next step is to <u>balance the reaction</u>:

2NaN_3~->~2Na~+~3N_2

We can continue with the <u>mol calculation</u> using the molar mass of

NaN_3 (65 g/mol), so:

3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3

Now, with the<u> molar ratio</u> between NaN_3  and N_2  we can <u>calculate the moles</u> of N_2  (2:3), so:

0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2

With the molar mass of N_2 we can <u>calculate the grams</u>:

0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2

I hope it helps!

5 0
3 years ago
HELP ME PLEASE ILL MARK U THE BRAINLIEST
ElenaW [278]

Answer:

pentene-alkanes-C5H10

octane-alkanes-C 8H 18

butene-alkene-c4h8

decane-alkane-c10h22

6 0
3 years ago
In the Bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is _______________ the ene
yawa3891 [41]

Answer:

greater than

Explanation:

4 0
3 years ago
Ethanedioic acid, a compound that is present in many vegetables, has a molar mass of 90.04 g/mol and a composition of 26.7% Carb
aleksandrvk [35]

Answer:

Empirical CHO2

Molecular C2H2O4

Explanation:

To determine the formulas, firstly, we need to divide the percentage compositions by the atomic masses.

Kindly note that the atomic mass of carbon, oxygen and hydrogen are 12, 16 and 1 respectively. We proceed with the division as follows:

C = 26.7/12 = 2.225

H = 2.2/1 = 2.2

O = 71.1/16 = 4.44375

We then proceed to divide by the smallest value which is 2.2 in this case

C = 2.25/2.2 = 1

H = 2.2/2.2 = 1

O = 4.44375/2.2 = 2

Thus, the empirical formula is CHO2

We now proceed to get the molecular formula as follows

[12+ 1 + 16(2) ]n = 90.04

45n = 90.04

n = 90.04/45 = 2

The molecular formula is :

C2H2O4

4 0
3 years ago
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