Ano ang mangyayari kung hindi mo gagamitin ang iyong talento?

As shown in the diagram, an inflated balloon released from rest moves horizontally with velocity "v". The velocity of the balloo

Mrac [35]

Answer:

i d k

but u fine as hell

Explanation:

8 0

2 years ago

Read 2 more answers

Which variable is not required to calculate the gibbs free-energy change?

xxMikexx [17]

All spontaneous processes release free energy

3 0

2 years ago

A car going at v = 29.7 m/s (67 mph) rounds a curve of radius R = 50.0 m, where the road is banked at an angle of θ = 30.0°. Wha

Nikolay [14]

Answer:

μ = 0.6

Explanation:

given,

speed of car = 29.7 m/s

Radius of curve = 50 m

θ = 30.0°

minimum static friction = ?

now,

writing all the forces acting along y-direction

N cos θ - f sinθ = mg

N cos θ -μN sinθ = mg

$N = \dfrac{m g}{cos\theta-\mu sin \theta}$

now, writing the forces acting along x- direction

N sin θ + f cos θ = F_{net}

N cos θ + μN sinθ = F_{net}

$\dfrac{m g}{cos\theta-\mu sin \theta}(cos \theta + \mu sin\theta)=F_{net}$

taking cos θ from nominator and denominator

$F_{net} =\dfrac{tan\theta + \mu}{1-\mutan\theta}. mg$

$\dfrac{mv^2}{r}=\dfrac{tan\theta + \mu}{1-\mutan\theta}. mg$

$\dfrac{v^2}{r}=\dfrac{tan\theta + \mu}{1-\mutan\theta}g$

$\mu=\dfrac{v^2 -r g tan\theta}{v^2tan\theta + r g}$

now, inserting all the given values

$\mu=\dfrac{29.7^2 -50 \times 9.8tan 30^0}{29.7^2\times tan 30^0 +50 \times 9.8}$

μ = 0.6

7 0

2 years ago

¿Cuál es la aceleración centrípeta de un móvil que recorre una

Lady bird [3.3K]

Answer:

a) a = 4.57 m/s², b) a = 6.48 m / s² , c) a = 1.42 m / s²,d) r = 82.3 m

Explanation:

The centripetal acceleration is the acceleration responsible for the change of direction of the acceleration vector and occurs in circular movements, the expression is

a = v² / r

let's apply this precaution to our cases

a) let's calculate

a = 8²/14

a = 4.57 m/s²

b) an automobile at v = 65 km / h (1000 m / 1km) (1 h / 3600 s) =18,055 m/s

let's reduce feet to meters

1 ft = 0.3048 m

r = 165 ft (0.3048 m / 1 ft) = 50.292 m

a = 18,055 2 / 50,292

a = 6.48 m / s²

c) we calculate

a = 1.25²2 / 1.1

a = 1.42 m / s²

d) we look for the radius

a = v² / r

r = v² / a

we reduce

v = 80 km / h (1000 m / 1km) (1h / 3600s) = 22.22 ms

r = 22.22²/6

r = 82.3 m

e) the cenripeta acceleration is used to take the curves on the highway,

Used in centrifuges to separate compounds

It is used in the games of the park of atraccio

Used in CD players and computer hard drives

5 0

2 years ago

A fairground ride consists of a large vertical drum that spins so

expeople1 [14]

Answer:

v = 3.84 m/s

Explanation:

In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:

$Centripetal\ Force = Frictional\ Force\\\\\frac{mv^2}{r} = \mu R = \mu W\\\\\frac{mv^2}{r} = \mu mg\\\\\frac{v^2}{r} = \mu g\\\\v = \sqrt{\mu gr}$

where,

v = minimum speed = ?

g = acceleration due to gravity = 9.81 m/s²

r = radius = 10 m

μ = coefficient of friction = 0.15

Therefore,

$v=\sqrt{(0.15)(9.81\ m/s^2)(10\ m)}$

6 0

2 years ago

Ano ang mangyayari kung hindi mo gagamitin ang iyong talento?​

Ano ang mangyayari kung hindi mo gagamitin ang iyong talento?