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3 years ago

What is the force that counteracts the thrust force for flight?

Physics

1 answer:

masha68 [24]3 years ago

8 0

Answer:

Drag

Explanation:

It is caused by air resistance and acts in the oooosite direction to the motion.

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The frequency is slowly increased. Once it passes the critical value fb, the student hears the ball bounce. There is now enough

vitfil [10]

Answer: g = acceleration = A*w^2 = A*(2*pi*fb)^2.

Explanation:

The ball bounces when the acceleration of the ball exceeds that of gravity. If A and fb are measured at that point, g = acceleration = A*w^2 = A*(2*pi*fb)^2.

3 0

3 years ago

A bullet is fired at a speed of 15 m/s from the edge of a cliff. The bullet strikes the ground 65 m from a height H. Find the fi

svet-max [94.6K]

Answer:

v=38.73m/s

Explanation:

u=15m/s

v =?

s=65m

g=9.81

v²=u²+2×g×s

v²=15²+2×9.81×65=1500.3

v=38.73m/s

8 0

3 years ago

In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope

zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude $g$ .

If we have the initial velocity $v_o$ and its angle $\theta$ , we can obtain the vertical component of the velocity $v_{oy}$ using trigonometry:

$v_{oy}=v_osin\theta$

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

$v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }$

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

$g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

Finally, from the equation of horizontal motion with constant speed, we have that:

$x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}$

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

$v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s} }{9.8\frac{m}{s^{2} } } =7.49m$

In words, the projectile travels 7.49m horizontally before it lands.

8 0

4 years ago

Why is thermal energy from the Sun transferred to Earth through electromagnetic waves instead of any other type of thermal energ

Pachacha [2.7K]

Answer:

Electromagnetic waves can travel through empty space.

Explanation:

Electromagnetic waves are defined as the waves that are created due to the vibrations between a magnetic field and an electric field.

Earth atmosphere is made up of several gases and spaces between them. Thermal energy from the sun require to pass through space by electromagnetic radiation. Electromagnetic waves can travel through empty space and that is why other type of waves are unable to transfer thermal energy.

Hence, the correct answer is "Electromagnetic waves can travel through empty space".

8 0

3 years ago

Read 2 more answers

When does a object have the greatest kinetic energy?

Rufina [12.5K]

When Object is at zero height, and there is no potential energy possess by the object then it exerts Greatest Kinetic energy in it's whole Journey

Hope this helps!

8 0

4 years ago