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3 years ago

4. How much work is done when you lift a 25 N box up to a 2 m shelf?

Physics

1 answer:

Semmy [17]3 years ago

6 0

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question

force = 25 N

distance = 2 m

We have

workdone = 25 × 2 = 50

We have the final answer as

Hope this helps you

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Bare free charges do not remain stationary when close together. To illustrate this, calculate the acceleration of two isolated p

Marta_Voda [28]

Answer:

Acceleration, $a=9.91\times 10^{15}\ m/s^2$

Explanation:

It is given that,

Separation between the protons, $r=3.73\ nm=3.73\times 10^{-9}\ m$

Charge on protons, $q=1.6\times 10^{-19}\ C$

Mass of protons, $m=1.67\times 10^{-27}\ kg$

We need to find the acceleration of two isolated protons. It can be calculated by equating electric force between protons and force due to motion as :

$ma=\dfrac{kq^2}{r^2}$

$a=\dfrac{kq^2}{mr^2}$

$a=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{1.67\times 10^{-27}\times (3.73\times 10^{-9})^2}$

$a=9.91\times 10^{15}\ m/s^2$

So, the acceleration of two isolated protons is $9.91\times 10^{15}\ m/s^2$ . Hence, this is the required solution.

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3 years ago

Who was the creator of sports

Elden [556K]

The first Olympic Games were in Greece

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3 years ago

A car battery has a rating of 170 ampere-hours. This rating is one indication of the total charge that the battery can provide t

Pavlova-9 [17]

Answer:

612000 C

Explanation:

Current, I, is given as the rate of flow of charge, that is:

I = Δq / Δt

where q = electric charge

t = time taken

This implies that:

Δq = I * Δt

The battery rating is 170 Ampere-hours, therefore:

Δq = 170 * 1 hour

But 1 hour = 3600 seconds;

=> Δq = 170 * 3600 = 612000 C

The total charge that the battery can provide is 612000 C.

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3 years ago

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Answer:

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3 years ago

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In a laboratory, you determine that the density of a certain solid is 5.23× 10 −6 kg/m m 3 . convert this density into kilograms

tamaranim1 [39]

Density is given as

$\rho = 5.23 * 10^{-6} kg/mm^3$

now we have to convert this density into $kg/m^3$

now we have

$1 m = 1000 mm$

$\rho = 5.23 * 10^{-6} \frac{kg}{(1*10^-3 m)^3}$

$\rho = 5.23 * 10^{-6} \frac{1*10^9 kg}{m^3}$

$\rho = 5.23 * 10^3 kg/m^3$

$\rho = 5230 kg/m^3$

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3 years ago