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Butoxors [25]
3 years ago
13

28° 51' 55" W

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
4 0

Answer: good                  

Explanation:  its fun

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Where is the ion charge located in the isotope symbol
Juliette [100K]
The ion charge located in the isotope symbol on the top right corner. <span>The number part of an </span>isotope's<span> name is the Mass Number (P + N). A negatively</span>charged ion<span> (anion) will have more Electrons than Protons. Cl 1- has one more electron than proton; 18 electrons, 17 protons. That's why its </span>charge<span> is 1-.</span>
3 0
3 years ago
Question 2 (10 points)
svet-max [94.6K]
4 infiltration percolation!! I think! Correct me if I’m wrong
6 0
4 years ago
Under certain conditions, the substance hydrobromic acid can be broken down to form hydrogen and bromine.
Lerok [7]

Answer:

1. 24.7g of Br2

2. 19.9g of HCl

Explanation:Please see attachment for explanation

7 0
4 years ago
How many moles of N2O5 are needed<br> to produce 7.90 g of NO2?
Roman55 [17]

Answer:

0.085 moles of  N₂O₅ are needed

Explanation:

Given data:

Mass of NO₂ produces = 7.90 g

Moles of N₂O₅ needed = ?

Solution:

2N₂O₅       →     4NO₂  + O₂

Number of moles of NO₂ produced :

Number of moles = mass/ molar mass

Number of moles = 7.90 g/ 46 g/mol

Number of moles = 0.17 mol

now we will compare the moles of NO₂   with N₂O₅.

                NO₂          :       N₂O₅

                  4            :          2

                0.17          :         2/4×0.17 = 0.085 mol

Thus, 0.085 moles of  N₂O₅ are needed.

4 0
3 years ago
Given the two reactions PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq), K3 = 1.89×10−10, and AgCl(aq)⇌Ag+(aq)+Cl−(aq), K4 = 1.25×10−4, what is the
Sergio [31]

Answer:

1.2\times 10^{-2}

Explanation:

The given reactions are:

PbCl2(aq)⇌Pb2+(aq)+2Cl−(aq)     K_3 = 1.89\times 10^{-10}

AgCl(aq)⇌Ag+(aq)+Cl−(aq)           K_4 = 1.25\times 10^{-4}

Required reaction is:

PbCl2(aq)+2Ag+(aq)⇌2AgCl(aq)+Pb2+(aq)

K_f = \frac{K_3}{K_4^2}\\=\frac{1.89\times 10^{-10}}{1.25\times 10^{-4}}^2\\=1.2\times 10^{-2}

4 0
4 years ago
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