How many moles of NH3 can be produced by the reaction of 2.00 g of N2 with 3.00 g H2?

2. Soil is made of <br> A. air<br> B. rocks<br> C. decomposed leaves<br> D. all of the above

Irina18 [472]

Answer:

B

Explanation:

<h2>Soil is a mixture of </h2><h2 /><h2>tiny particles of rock,</h2>

<h2>dead plants and animals </h2>

<h2>,air and water.</h2>

3 0

3 years ago

Read 2 more answers

The calvin cycle and the krebs are referred to as cycles of chemical reactions because they

Schach [20]

Answer:

The options are

a. occur inside organelles. b. start over continually. c. are part of the carbon cycle. d. allow energy to flow in ecosystems.

The answer is b. Start over continually

Explanation:

The two cycles involves a continuous process as long as the reactants are present under suitable conditions. The cycle happens all the time due to it being necessary to produce important products all the time for the body system.

A good example involves the existing Carbon dioxide and water reacting together to get converted into substance that could provide energy (ATP and NADH) such as Glucose.

8 0

3 years ago

13. Find the total number of atoms present in the following molecules. a. 5 H₂O b. Zn Cl₂

olganol [36]

Answer:

A= 15 atoms B= 3

Explanation:

5 x 2 + 5 x 1

3 + 2 x 1

5 0

3 years ago

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

Stella [2.4K]

Answer:

See explanation.

Explanation:

Hello,

In this case, we can show how the empirical formula is found by following the shown below procedure:

1. Compute the moles of carbon in carbon dioxide as the only source of carbon at the products:

$n_C=0.01962molCO_2*\frac{1molC}{1molCO_2} =0.01962molC$

2. Compute the moles of hydrogen in water as the only source of hydrogen at the products:

$n_H=0.01961molH_2O*\frac{2molH}{1molH_2O}=0.03922molH$

3. Compute the mass of oxygen by subtracting the mass of both carbon and hydrogen from the 0.4647-g sample:

$m_O=0.4647g-0.01962molC*\frac{12gC}{1molC}-0.03922molH*\frac{1gH}{1molH} =0.1900gO$

4. Compute the moles of oxygen by using its molar mass:

$n_O=0.1900gO*\frac{1molO}{16gO}=0.01188molO$

5. Divide the moles of carbon, hydrogen and oxygen by the moles of oxygen (smallest one) to find the subscripts in the empirical formula:

$C=\frac{0.01962}{0.01188}=1.65\\ \\H=\frac{0.03922}{0.01188} =3.3\\\\O=\frac{0.01188}{0.01188} =1$

6. Search for the closest whole number (in this case multiply by 2):

$C_3H_6O_2$

Moreover, the empirical formula suggests this compound could be carboxylic acid since it has two oxygen atoms, nevertheless, this is not true since the molar mass is 222.27 g/mol, therefore, we should compute the molar mass of the empirical formula, that is:

$M=12*3+1*6+16*2=74g/mol$

Which is about three times in the molecular formula, for that reason, the actual formula is:

$C_9H_{18}O_6$

It suggest that the compound has a highly oxidizing character due to the presence of oxygen, therefore, we cannot predict the distribution of the functional groups as it could contain, carboxyl, carbonyl, hydroxyl or even peroxi.

Best regards.

6 0

3 years ago

How many grams of sodium bicarbonate are needed to completely react with a 0.892 m phosphoric acid solution that contains to 45.

SVETLANKA909090 [29]

Answer:

umm idk if I was right or not

7 0

3 years ago