<h3><u>Answer;</u></h3>
= 3032.15 kPa
<h3><u>Explanation;</u></h3>
Using the equation;
PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.
Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles
Therefore;
Pressure = nRT/V
= (5 × 0.08206 × 547)/7.5 L
= 29.925 atm
But; 1 atm = 101325 pascals
Hence; Pressure = 3032150.63 pascals
<u>= 3032.15 kPa</u>
Are there answer choices or is this a write in answer?
Answer: 131 g of bromine is required.
Explanation:
The balanced equation will be :
To calculate the moles, we use the equation:
moles of 
According to stoichiometry :
2 moles of require = 3 moles of 
Thus 0.544 moles of require=
of
Mass of 
Thus 131 g of bromine is required.
Each atom will be attracted to both nuclei if the two atoms get close then the nuclei will repel each other
