1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KatRina [158]
3 years ago
9

Which physical property can NOT be observed using 5 senses without changing the chemical makeup of the object that you are obser

ving?
A. Mass

B. Color

C. Ability to conduct heat

D. Texture​
Chemistry
1 answer:
bonufazy [111]3 years ago
4 0
Ummm i believe it’s C
You might be interested in
What would make oppositely charged objects attract each other more?
stepladder [879]
<h2>Answer:</h2>

A). Increasing the positive charge of the positively charged object and increasing the negative charge of the negatively charged object.

<h2>Explanation:</h2>

3 0
3 years ago
For each equation , write all possible mole ratios . A. 2HgO(s)&gt;2Hg(l)+O2(g) B. 4NH3(g)+6NO(g)&gt;5N2(g)+6H2O(l)
Dafna11 [192]

A) For balanced chemical equation: 2HgO(s) → 2Hg(l) + O₂(g).

1) Mole ratio 1: n(HgO) : n(Hg) = 2 : 2 (1 : 1).

2) Mole ratio 2: n(HgO) : n(O₂) = 2 : 1.

3) Mole ratio 3: n(Hg) : n(O₂) = 2 : 1.

B) Balanced chemical equation: 4NH₃(g) + 6NO(g) → 5N₂(g) + 6H₂O(l).

1) Mole ratio 1: n(NH₃) : n(NO) = 4 : 6 (2 : 3).

2) Mole ratio 2: n(NH₃) : n(N₂) = 4 : 5.

3) Mole ratio 3: n(NH₃) : n(H₂O) = 4 : 6 (2 : 3).

4) Mole ratio 4: n(NO) : n(N₂) = 6 : 5.

5) Mole ratio 5: n(NO) : n(H₂O) = 6 : 6 (1 :1).

6) Mole ratio 6: n(N₂) : n(H₂O) = 5 : 6.

3 0
3 years ago
Read 2 more answers
An ideal gas is stored in a container at constant volume. If the temperature (T) were increased to 3T, what would be the change
Olin [163]
According to Gayle Lusac's law, pressure is proportional to absolute temperature of a gas. Thus:
P/T = constant

So if the temperature becomes 3T, the pressure would increase to 3P
6 0
3 years ago
Read 2 more answers
How many moles of NaOH are in 13.25 mL of 0.323 M NaOH?
adell [148]
M=mol/L, 0.323M=mol/0.01325. Rework to solve for mol and bam! (I.e. times the two numbers)
7 0
3 years ago
Naphthalene, commonly found in moth balls, is composed of 93.7% carbon and 6.3% hydrogen. The molar mass of naphthalene is 128 g
Vikki [24]

Answer:

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

Explanation:

Centesimal composition means that in 100 g of compound we have x g of the element. Therefore in 100 g of naphthalene we have:

93.7 g of C

6.3 g of H

Let's make a rule of three:

In 100 g of naphthalene we have 93.7 g of C  and 6.3 g of H

In 128 g of naphthalene we would have:

128 . 93.7 / 100 = 120 g of C

128.  6.3 / 100 = 8 g of H

We convert the mass to moles, by molar mass:

120 g . 1mol / 12 g = 10 moles C

8 g . 1mol/ 1g = 8 moles H

Molecular formula naphthalene → C₁₀H₈

Empirical formula naphthalene → C₅H₄

(The sub-index of each element is divided by the largest possible number)

6 0
4 years ago
Read 2 more answers
Other questions:
  • The U.S. requires automobile fuels to contain a renewable component. The fermentation of glucose from corn produces ethanol, whi
    5·1 answer
  • Why do the two elements silver and iron have different properties?
    8·1 answer
  • How many grams can be prepared until equilibrium is attained? carbon disulfide is prepared by heating sulfur and charcoal. the c
    7·1 answer
  • What is one observation you can make aboit venus​
    8·1 answer
  • Why is copper a good electrcity conducter
    10·2 answers
  • The alignment of the Moon and Sun has an affect on Earth's ocean tides. What force
    7·1 answer
  • What is a factor of matter
    6·1 answer
  • 6. India is a country connected to the continent of Asia. India used to be far apart
    7·1 answer
  • True or False: longitudinal waves move up and down
    12·2 answers
  • You have just weighed the same beaker twice, obtaining the following measurements. 50.12 g and 50.25 g. The accepted value of th
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!