Answer:
Iodide> Bromide > chloride > flouride
Explanation:
During a nucleophilic substitution reaction, a nucleophilie replaces another in a molecule.
This process may occur via an ionic mechanism (SN1) or via a concerted mechanism (SN2).
In either case, the ease of departure of the leaving group is determined by the nature of the C-X bond. The stronger the C-X bond, the worse the leaving group will be in nucleophilic substitution. The order of strength of C-X bond is F>Cl>Br>I.
Hence, iodine displays the weakest C-X bond strength and it is thus, a very good leaving group in nucleophillic substitution while fluorine displays a very high C-X bond strength hence it is a bad leaving group in nucleophilic substitution.
Therefore, the ease of the use of halide ions as leaving groups follows the trend; Iodide> Bromide > chloride > flouride
Hi~~
H2O, commonly known as water, is definitely a compound.
David's conclusion is wrong because the hydrogen gas combined with oxygen from the air to form dihydrogen monoxide, also known as water.
Answer:
In chemistry, "concentrated" refers to a relatively large quantity of substance present in a unit amount of a mixture. Usually, this means there is a lot of a solute dissolved in a given solvent. A concentrated solution contains the maximum amount of solute that can be dissolved.
Explanation:
Answer:
29.92grams of PbSO4
Explanation:
lead (iV) oxide = PbO2 = Molar mass: 239.2 g/mol
lead (ll) sulfate = PbSO4 = Molar mass: 303.26 g/mol
PbO2 = PbSO4
1:1 ratio
Pb = Lead
Lead has an oxidation number of 4+
O = Oxygen
Oxygen has an oxidation number of 2-
PbO2 + 4H+ + SO4 2- + 2e- = PbSO4(s) + 2H2O
Ok so the above would be the likely complete reaction, though we don't really need this as we already know the ratio is 1:1.
23.6g of PbO2
23.6/239.2 = 0.09866 Moles of PbO2
Since we have a 1:1 ratio we know that the same number of moles of PbSO4 are produced and since we know the molar mass it's simply molar mass multiplied by number of moles.
303.26 x 0.09866 = 29.92grams of PbSO4
