1. 842g of NaOH will form 547.3 g of Al(OH)₃
2. The yield is 93.55%
<u>Explanation:</u>
3NaOH + Al → Al(OH)₃ + 3Na
1.
Molar mass of NaOH = 40 g/mol
Molar mass of Al = 27 g/mol
Molar mass of Al(OH)₃ = 78 g/mol
According to the balanced equation:
3 moles of NaOH requires 1 mole of Al to form 1 mole of Al(OH)₃
The ratio of NaOH : Al : Al(OH)₃ = 3 : 1 : 1
3 X 40 g of NaOH reacts with 27 g of Al to form 78 g of Al(OH)₃
120 g of NaOH + 27g of Al → 78 g of Al(OH)₃
120g of NaOH form 78g of Al(OH)₃
1g of NaOH will form g of Al(OH)₃
842g of NaOH will form of Al(OH)₃
= 547.3 g of Al(OH)₃
Therefore, 842g of NaOH will form 547.3 g of Al(OH)₃
2. Only 512 g of Al(OH)₃ is formed
Yield % = ?
Therefore, the yield is 93.55%
Answer:
não sei......................
The advantage of sexual reproduction is that the offspring might not get the genetic disease carried by one of the parents since a mixture of two genetics are involved in the production of offspring that shares half of each’s genetics it can be possible that genetic diseases might be skipped in the offspring.
Unlike sexual reproduction asexual reproduction has chances of genetic caring of diseases because the genes carry genetic information completely from the parent gene.
Question options:
1. Insoluble
2. Soluble
3. Solvable
Answer:
Soluble
Explanation:
The solubility is a chemical property referring to the ability of the solute to dissolve in a solvent and form a homogeneous mixture (solution). It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium.
<u>Therefore, a substance is soluble in a particular liquid if it is able to dissolve in a solvent.</u>
Answer:
158 mL
158 mL of 0.1 M of HCl is required to react completely with 1 g mixture of Na2CO3 and NaHCO3, containing equimolar amounts of both
Explanation:
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btw masoom bachi copied me~