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ss7ja [257]
2 years ago
12

Required information

Physics
1 answer:
Liono4ka [1.6K]2 years ago
4 0

Answer:

hmm OK is there any news about London is modern enough or

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Briefly describe the formation of the planets from the solar nebula
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6 0
3 years ago
An electric field of intensity 3.80 kN/C is applied along the x-axis. Calculate the electric flux through a rectangular plane 0.
lakkis [162]

Answer: 1.55 x 10⁴ Nm²c^-1

Explanation: The electric flux, electric field intensity and area are related by the formulae below.

Φ= EAcosθ,

Where Φ= electric flux (Nm²c^-1)

E =electric field intensity (N/m²)

A = Area (m²)

θ= this is angle between the planar area and the magnetic flux

For our question E=3.80KN/c= 3800 N/c

A= 0.700 x 0.350= 0.245m²

θ= 0° ( this is because the electric field was applied along the x axis, thus the electric flux will be parallel to the area).

Hence Φ= 3800 x 0.245 x cos(0)

= 3800 x 0.245 x 1 (value of cos 0° =1)

= 1.55 x 10⁴ Nm²c^-1

Thus the electric field is 1.55 x 10⁴ Nm²c^-1

4 0
4 years ago
Why do all freely falling objects have the same acceleration
iren2701 [21]
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8 0
3 years ago
Read 2 more answers
A worker pushes horizontally on a large crate with a force of 200 N, and the crate is moved 3.5 m. How much work was done in Jou
sattari [20]

Work = (force) x (distance) =

           (200 N) x (3.5 m)  =  <em>700 joules</em>


6 0
4 years ago
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yanalaym [24]

Answer:

yes bc it washed it away so

Explanation:

(:

4 0
3 years ago
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