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Irina-Kira [14]
3 years ago
7

Which element is classified as a

Chemistry
1 answer:
Yuki888 [10]3 years ago
5 0

Answer: Boron

Explanation:

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What is the oxidation state of cr in CrPO4 and Cr3(PO4)2?
soldi70 [24.7K]

Answer:

Explanation:

Oxidation state of Cr in CrPO₄

As a general rule, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.

The compound above is in its neutral state and we sum all the oxidation numbers and equate to zero:

The oxidation number of P is -2

                                           O is -2

Let the oxidation number of Cr be x:

                              x + (-2) + 4(-2) = 0

                              x -2-8 = 0

                               x -10 = 0

                                x = +10

For Cr in Cr₃(PO₄)₂

         Using the same rule:

        2(x) + 2[-2 + 4(-2)] = 0

           2x + 2(-2-8) = 0

            2x -20 = 0

                x = +10

6 0
3 years ago
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How do mixtures form?
LenKa [72]

Answer:

A mixture is created when two or more different substances are physically combined and can be separated back into its original substances. A chemical reaction occurs when two or more substances are combined to form a new substance and cannot be separated back into its original substances.

Explanation:

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3 years ago
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Why is a shoe considered individual evidence
vlada-n [284]
Because someone was wearing it and their dna could be in it i’m guessing
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3 years ago
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On combustion, 1.0 L of a gaseous compound of hydrogen, carbon, and sulfur gives 2.0 L of CO2, 3.0 L of H2O vapor, and 1.0 L of
Murrr4er [49]

Answer:

The empirical formula of the organic compound is  = C_2H_6S_1

Explanation:

At STP, 1 mole of gas occupies 22.4 L of volume.

Moles of CO_2 gas at STP occupying 2.0 L = n

n\times 22.4L=2.0L

n=\frac{2.0 L}{22.4 L}=0.08929 mol

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of H_2O gas at STP occupying 3.0 L = n'

n'\times 22.4L=3.0L

n'=\frac{3.0 L}{22.4 L}=0.1339 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of SO_2 gas at STP occupying 1.0 L = n''

n''\times 22.4L=1.0L

n''=\frac{1.0 L}{22.4 L}=0.04464 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

Moles of carbon , hydrogen and sulfur constituent of that organic compound .

Moles of carbon in 0.08920 mol = 1 × 0.08920 mol = 0.08920 mol

Moles of hydrogen in 0.1339 moles of water vapor = 2 × 0.1339 mol = 0.2678 mol

Moles of sulfur in 0.04464 mol = 1 × 0.04464 mol = 0.04464 mol

For empirical; formula divide the least number of moles from all the moles of elements.

carbon = \frac{0.08920 mol}{0.04464 mol}=2

Hydrogen =  \frac{0.2678 mol}{0.04464 mol}=6

Sulfur = \frac{0.04464 mol}{0.04464 mol}=1

The empirical formula of the organic compound is  = C_2H_6S_1

3 0
3 years ago
What is the significance of the limiting reagent in a reaction?
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4 years ago
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