The order of the steps, from first to last, is as follows based on the information in the question:
1. Salt is broken down into cations and anions.
2. Anion hydration.
3. Cation hydration.
4. Cations and anions that have been dissolved start to settle as a solid salt.
5. The rate of dissolution and recrystallization are equal.
Without hydration of the ions, the cation and anion cannot get separated. The three processes of ion dissociation, cation hydration, and anion hydration must all take place at once.
<h3>Why water is an effective solvent?</h3>
Water is a great solvent that can dissolve a wide variety of compounds due to its polarity and capacity to create hydrogen bonds.
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Answer:
C6H12O6 + 6O2 → 6CO2 + 6H2O
Explanation:
Cellular respiration occurs in the mitochondria of cells. It is a process in which sugar is combined with oxygen to produce energy, water and carbon dioxide. This is the major process by which energy is released in living organisms.
Aerobic respiration involves a series of chemical reactions. These reactions commence with sugar and oxygen then it produces carbon dioxide and water according to the reaction equation; C6H12O6 + 6O2 → 6CO2 + 6H2O.
Answer:
a) Schmidt number
Explanation:
Prandtl number in heat transfer is analogues to Schmidt number in mass transfer.
Prandtl number in heat transfer is the ration of momentum diffusivity to the heat diffusivity.
Whereas, Schmidt number in mass transfer is the ratio of momentum diffusivity to the mass diffusivity.
Explanation:
The given data is as follows.
= 0.483, ![[Co^{3+}]](https://tex.z-dn.net/?f=%5BCo%5E%7B3%2B%7D%5D)
= 0.173 M,
![[Co^{2+}]](https://tex.z-dn.net/?f=%5BCo%5E%7B2%2B%7D%5D)
= 0.433 M, ![[Cl^{-}]](https://tex.z-dn.net/?f=%5BCl%5E%7B-%7D%5D)
= 0.306 M,
= 9.0 atm
According to the ideal gas equation, PV = nRT
or, P = 
Also, we know that
Density = 
So, P = MRT
and, M = 
= 
= 
= 0.368 mol/L
Now, we will calculate the cell potential as follows.
E = ![E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}](https://tex.z-dn.net/?f=E%5E%7Bo%7D%20-%20%5Cfrac%7B0.0591%7D%7Bn%7D%20log%20%5Cfrac%7B%5BCo%5E%7B2%2B%7D%5D%5E%7B2%7D%5BCl_%7B2%7D%5D%7D%7B%5BCo%5E%7B3%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E%7B2%7D%7D)
= 
= 
= 
= 0.483 - 0.0185
= 0.4645 V
Thus, we can conclude that the cell potential of given cell at 
is 0.4645 V.
