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Black_prince [1.1K]
3 years ago
6

1. Which sample contains a total of 9.0 * 10 ^ 23 atoms ? A) 0.50 mole of HCI B) 0.75 mole of H 2 O C) 1.5 moles of Cu D) 1.5 mo

les of H 2
Chemistry
1 answer:
Alchen [17]3 years ago
8 0

c. 1.5 moles of Cu will contain a total of 9.0 * 10 ^ 23 atoms.

Explanation:

To convert moles into atoms,  the molar amount and number of atom is multiplied by Avagadro's number.

Avagadro's number is 6.022×10^{23}  

So applying the formula in the given sample:

A) 0.5×6.022×10^{23}

   3.01×10^{23} atoms.

B) 0.75 mole of H20

O.75×6.022×10^{23}

= 4.5166×10^{23}  atoms.

C) 1.5 moles of Cu

  1.5×6.022×10^{23}

  =  9.033×10^{23}

D). 1.5 moles of H2

1.5 × 2 × 6.022 × 10^{23}

= 18.066 × 10^{23} atoms   because H2 is 2 moles of hydrogen.

Atom is the smallest entity of matter having property of the element to which it is a part.

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Vlad1618 [11]
I know for number 4 the answer is c, sorry I can't help with the others.
5 0
3 years ago
As with other ionic compounds, potassium bromate, KBrO3, dissociates into ions when it dissolves in water. If 13.8 g of KBrO3 is
chubhunter [2.5K]

Answer:

ΔH of dissociation is 38,0 kJ/mol

Explanation:

The dissociation reaction of KBrO₃ is:

<em>KBrO₃ → K⁺ + BrO₃⁻ </em>

This dissolution consume heat that is evidenced with the decrease in water temperature.

The heat consumed is:

q = CΔTm

Where C is specific heat of water (4,186 J/mol°C)

ΔT is the temperature changing (18,0°C - 13,0°C = 5,0°C)

And m is mass of water (150,0 mL ≈ 150,0 g)

Replacing, heat consumed is:

q = 3139,5 J ≡ 3,14 kJ

13,8 g of KBrO₃ are:

13,8 g×(1mol/167g) = 0,0826 moles

Thus, ΔH of dissociation is:

3,14kJ / 0,0826mol = <em>38,0 kJ/mol</em>

<em></em>

I hope it helps!

3 0
3 years ago
the vapor pressure of a naqueous solution is found to be 24.9 mmgh at 25C. what is the mole fraction of solute in this solution?
Gekata [30.6K]

Answer:

Mole fraction of solute is 0.0462

Explanation:

To solve this we use the colligative property of lowering vapor pressure.

First of all, we search for vapor pressure of pure water at 25°C  = 23.8 Torr

Now, we convert the Torr to mmHg. Ratio is 1:1, so 23.8 Torr is 23.8 mmHg.

Formula for lowering vapor pressure is:

ΔP = P° . Xm

Where ΔP = P' (Vapor pressure of solution) - P° (Vapor pressure of pure solvent)

Xm = mole fraction

24.9 mmHg - 23.8 mmHg = 23mmHg . Xm

Xm = (24.9 mmHg - 23.8 mmHg) /  23mmHg

Xm = 0.0462

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liubo4ka [24]
Zinc has 35 neutrons
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4 years ago
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Zina [86]

Answer:

C

Explanation:

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3 years ago
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