<u>Answer:</u>
Maximum height = 2040 m
<u>Explanation:</u>
We can solve the problem using kinematics.
Consider the vertical motion of the object and use the equation:
where:
• v = final velocity (0 m/s, because when the object is at max. height, it has no vertical velocity)
• u = initial velocity (400sin30° m/s ⇒ vertical component of 400 m/s at 30° to horizontal)
• a = acceleration (-9.81 m/s²; considering upward acceleration to be negative)
• s = displacement (? m; this represents the max. height of the object),
Substitute the values into the equation and solve for <em>s </em>:
⇒
⇒ (3 s.f.)