All categories

3 years ago

I need to solve for d

Engineering

2 answers:

mrs_skeptik [129]3 years ago

6 0

Answer:

it's not included

Explanation:

plz exact ur explain

KonstantinChe [14]3 years ago

4 0

Answer:

si amor

Explanation:

Hoiykñjdnlklbutrk

You might be interested in

Put four red LED as a straight line and connect each of them to a corresponding analog output. Connect a potentiometer to a 5 Vo

N76 [4]

Explanation:

There has been no information about related to which programming language is to be used, writing code algorithm.

Defining I/O's ;

Analogue output

A01, A02, A03,AO4

Analogue Input;

AI_1 // potentiometer input

// Based on controller used, assign channels to I/O's

// code

int voltage

Voltage = AI_1;

If (Voltage > 0 && Voltage < 1.25)

{

A01 = voltage

A02 = 0;

A03= 0

AO4= 0

}

If (Voltage > 1.25 && Voltage < 2.5)

{

A01 = 1.25

A02 = (Voltage -1.25);

A03= 0

AO4= 0

}

If (Voltage > 2.5 && Voltage < 3.75)

{

A01 = 1.25

A02 = 1.25

A03= (Voltage - 2.5);

AO4= 0

}

else

{

A01 = 1.25

A02 = 1.25

A03= 1.25

AO4= (Voltage - 3.75);

}

return

3 0

3 years ago

Rudy has changed his college major so many times that it will take him six years to graduate. Since his parents have pointedly o

Sav [38]

Answer:

moratorium

Explanation:

4 0

3 years ago

In a medical lab, Sandrine is working to isolate one element from a sample of liquid material. She uses a centrifuge, a machine

Ludmilka [50]

Answer:

Explanation:

4 0

2 years ago

What size resistor would produce a current flow of 5 Amps with a battery voltage of 12.6 volts

Debora [2.8K]

Answer:

resistance = 2.52 ohms

Explanation:

from the formula

V =IR

Voltage = (current)(resistance)

Resistance =

R= 2.52 ohms

5 0

3 years ago

A solid steel shaft has to transmit 100 kW at 160 RPM. Taking allowable shear stress at 70 Mpa, find the suitable diameter of th

MA_775_DIABLO [31]

Answer:

The diameter of the shaft is 80.5 mm.

Explanation:

Torsion equation is applied for the diameter of the solid shaft.

Step1

Given:

Power of the shaft is 100 kw.

Revolution per minute is 160 RPM.

Allowable shear stress is 70 Mpa.

Maximum torque is 20% more than the mean torque.

Step2

Mean torque is calculated as follows:

$P=T\omega$

$P=T(\frac{2\pi N}{60})$

$100\times 1000=T(\frac{2\pi 160}{60})$

T=5968.31 N-m

Step3

Maximum torque is calculated as follows:

$T_{max}=(1+\frac{20}{100})T$

$T_{max}=1.2T$

$T_{max}=1.2\times 5968.31$

T_{max}=7161.97 N-m

Step4

Apply torsional equation for diameter of shaft as follows:

$\tau _{max}=\frac{T_{max}}{\frac{\pi d^{3}}{16}}$

$70\times 10^{6}=\frac{7161.97}{\frac{\pi d^{3}}{16}}$

$d^{3}=5.211\times 10^{-4}$

d=0.0805 m

or,

d=80.5 mm

Thus, the diameter of the shaft is 80.5 mm.

7 0

3 years ago