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3 years ago

I need to solve for d

Engineering

2 answers:

mrs_skeptik [129]3 years ago

6 0

Answer:

it's not included

Explanation:

plz exact ur explain

KonstantinChe [14]3 years ago

4 0

Answer:

si amor

Explanation:

Hoiykñjdnlklbutrk

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Why is using the proper joining technique important? What could go wrong if the wrong joining technique is used?

Alex73 [517]

Answer:

Explanation:

Using the proper technique is incredibly important because it prevents the materials being joined from breaking and/or causing an accident. If the wrong joining technique is used the materials may not hold in place and come apart easily instead. Also, some joining techniques are not meant for some materials and may instead cause the material to become weak and brittle causing it to break apart almost immediately.

5 0

3 years ago

Which Car is more aerodynamic

Lana71 [14]

Answer:

The red one

Explanation:

not acturlly a thing between them so i might be wrong

5 0

3 years ago

Read 2 more answers

What’s the number of gold atoms in a nanogram? a picogram?

zvonat [6]

Answer :

The number of gold atoms in nanogram is, $3.057\times 10^{12}$

The number of gold atoms in picogram is, $3.057\times 10^{9}$

Explanation :

As we know that the molar mass of gold is, 196.97 g/mole. That means, 1 mole of gold has 196.97 grams of mass of gold.

As we know that,

1 mole contains $6.022\times 10^{23}$ number of atoms.

First we have to determine the number of gold atoms in a nanogram.

As, 196.97 grams of gold contains $6.022\times 10^{23}$ number of gold atoms

And, 1 grams of gold contains $\frac{1g}{196.97g}\times (6.022\times 10^{23})$ number of gold atoms

So, $10^{-9}$ nanograms of gold contains $\frac{1g}{196.97g}\times (10^{-9})\times (6.022\times 10^{23})=3.057\times 10^{12}$ number of gold atoms

The number of gold atoms in nanogram is, $3.057\times 10^{12}$

Now we have to determine the number of gold atoms in a picogram.

As, 196.97 grams of gold contains $6.022\times 10^{23}$ number of gold atoms

And, 1 grams of gold contains $\frac{1g}{196.97g}\times (6.022\times 10^{23})$ number of gold atoms

So, $10^{-12}$ picograms of gold contains $\frac{1g}{196.97g}\times (10^{-12})\times (6.022\times 10^{23})=3.057\times 10^{9}$ number of gold atoms

The number of gold atoms in picogram is, $3.057\times 10^{9}$

8 0

3 years ago

Daniel Wiseman, a scientist for Gres-Trans Corp., wants to determine if the flow rate of a particular material changes with diff

kiruha [24]

Answer: C. There is no relationship

Explanation:

At the various temperatures, the flow rates do not seem to show any relation as similar temperatures can yield different flow rates.

The flow rates neither appear to generally increase nor decrease as a result of a decrease or an increase in temperature which means that there is a lack of a positive, negative and curvilinear relationship.

There is simply no relationship.

4 0

3 years ago

You are performing a machining operation that approximates orthogonal cutting. Given that the chip thickness prior to chip forma

Mnenie [13.5K]

Answer:

shear plane angle = 31.98°

shear strain = cot ( 31.98° ) + tan ( 31.98 - 10 )

B) shear strength = 7339.78

Explanation:

a) Determine the shear plane angle and shear strain

Given data :

Chip thickness before chip formation = 0.5 inches

Chip thickness after separation = 1.125 inches

rake angle ( ∝ ) = 10°

shear plane angle : Tan ∅ = $\frac{rcos\alpha }{1-sin\alpha }$ ----- ( 1 )

r = chip thickness ratio = 0.5 / 1.125 = 0.4444

back to equation 1 : Tan ∅ = ( 0.444 ) * cos 10 / 1 - sin 10

Tan ∅ = 0.4444 * 0.9848 / 1 - 0.1736 = 0.5296

hence ∅ = tan^-1 ( 0.5296 ) = 31.98°

shear strain : R = cot ∅ + tan ( ∅ - ∝ ) ---------- ( 1 )

R = cot ( 31.98° ) + tan ( 31.98 - 10 )

B) determine the shear strength of the material

cutting force = 1559 N

thrust force = 1271 N

width of cut ( diameter ) = 3.0 mm

shear strength = c + σ.tan ∅

c = cohesion force = 1271 * 3 = 3813

σ = normal stress = F / A = 1559 / π/4 * ( 0.5 )^2 = 1559 / 0.1963 = 7941.94

hence : shear strength of material = 3813 + 7941.94 * 0.6244 = 7339.78

3 0

3 years ago