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3 years ago

Balance the following equations by inserting the proper coefficients.

Chemistry

2 answers:

kozerog [31]3 years ago

7 0

Answer : The given balanced equations will be,

$CH_4+2O2\rightarrow CO_2+2H_2O$

$CaCl_2+2AgNO_3\rightarrow Ca(NO_3)_2+2AgCl$

$C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O$

Explanation :

Balanced equation : In the balanced equation, the individual elements present on reactant side must be equal to the elements present on the product side.

The given balanced equations will be,

$CH_4+2O2\rightarrow CO_2+2H_2O$

$CaCl_2+2AgNO_3\rightarrow Ca(NO_3)_2+2AgCl$

$C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O$

Montano1993 [528]3 years ago

6 0

1212. 1212. 1323........

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11111nata11111 [884]

Answer:

The molality of the glycerol solution is 2.960×10^-2 mol/kg

Explanation:

Number of moles of glycerol = Molarity × volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles

Mass of water = density × volume = 0.9982 g/mL × 998.7 mL = 996.90 g = 996.90/1000 = 0.9969 kg

Molality = number of moles of glycerol/mass of water in kg = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg

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insens350 [35]

Answer:

The percentage efficiency of the electrical element is approximately 82.186%

Explanation:

The given parameters are;

The thermal energy provided by the stove element, $H_{supplied}$ = 3.34 × 10³ J

The amount thermal energy gained by the kettle, $H_{absorbed}$ = 5.95 × 10² J

The percentage efficiency of the electrical element in heating the kettle of water, η%, is given as follows;

$\eta \% = \dfrac{H_{supplied} - H_{absorbed} }{H_{supplied}} \times 100$

Therefore, we get;

$\eta \% = \dfrac{3.34 \times 10^3 - 5.95 \times 10^2}{3.34 \times 10^3} \times 100 = \dfrac{549}{668} \times 100 \approx 82.186 \%$

The percentage efficiency of the electrical element, η% ≈ 82.186%.

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