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Shalnov [3]
3 years ago
13

Calcium nitrate dissolves as follows: . how many moles of ca(no 3) 2 are required to make 2.0 liters of solution in which the no

3 - concentration is 0.20 m?
Chemistry
2 answers:
padilas [110]3 years ago
8 0
<span>If the volume of the solution is 2.0 liters and the concentration of NO3 - is 0.20 m, the number of mol of NO3- in the solution would be:
mol= volume * concentration= 2 liters * 0.2 mol/liter= 0.4 mol
</span><span>
The equation of ion formed by ca(no 3) 2 would be:
</span><span>Ca(NO3)2 ==> 1 Ca + 2 NO3
For every 1 mol of </span>Ca(NO3)2 will produce 2 mol of NO3-. So, the amount of Ca(NO3)2 needed to make 0.4 mol of NO3- would be: 0.4 mol / (2/1)= 0.2 mol<span>
</span>
Naily [24]3 years ago
8 0

Answer : The number of moles of Ca(NO_3)_2 required are, 0.2 moles

Explanation :

First we have to calculate the moles of NO_3^-.

\text{Moles of }NO_3^-=\text{Molarity of }NO_3^-\times \text{Volume of solution}=0.20M\times 2.0L=0.4mole

Now we have to calculate the moles of Ca(NO_3)_2.

The dissociation chemical reaction will be,

Ca(NO_3)_2\rightarrow Ca^{2+}+2NO_3^-

From this reaction we conclude that,

As, 2 moles of NO_3^- obtained from 1 mole of Ca(NO_3)_2

So, 0.4 moles of NO_3^- obtained from \frac{0.4}{2}=0.2 mole of Ca(NO_3)_2

Therefore, the number of moles of Ca(NO_3)_2 required are, 0.2 moles

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