Answer : The number of moles of
required are, 0.2 moles
Explanation :
First we have to calculate the moles of
.

Now we have to calculate the moles of
.
The dissociation chemical reaction will be,

From this reaction we conclude that,
As, 2 moles of
obtained from 1 mole of 
So, 0.4 moles of
obtained from
mole of 
Therefore, the number of moles of
required are, 0.2 moles