LD50 is defined as the lethal dose 50% which describes the amount of material required to kill 50% of the testing population. It is given in units of mg of chemical per kg of bodyweight of the recipient.
Comparing hydrogen peroxide and acetic acid, we see that peroxide has a lower LD50 of 900 mg/kg, with acetic acid having LD50 = 3310 mg/kg. When comparing LD50 values, the smaller value will be the more toxic compound. What this means is that in this case, a smaller amount of peroxide is required to kill 50% of the testing population compared to acetic acid.
Therefore, 3% hydrogen peroxide is more hazardous to consume.
Answer:
subtract the answer it'll get you that.
Explanation:
Answer:
Yes, acetic acid could be used, but it would not be as effective as acetyl chloride or acetic anhydride. ... However, the acetic anhydride would still be reacting with an alcohol, so nothing changes in that respect. Also, the reaction would need to be done in basic solution.
Answer:
12
Explanation:
You will need a chemical equation with masses and molar masses, so let’s gather all the information in one place.
: 258.21 18.02
KAl(SO₄)₂·xH₂O ⟶ KAl(SO₄)₂ + xH₂O
Mass/g: 4.74 2.16
Step 1. Calculate the mass of the KAl(SO₄)₂.
Mass = 4.74 g – 2.16 g = 2.58 g.
Step 2. Calculate the moles of each product.
Step 3. Calculate the molar ratio of the two products.
1 mol of KAl(SO₄)₂ combines with 12 mol H₂O, so x = 12.