The Percent composition of MgO is 60.304 % and 39.696 % respectively.
<h3>
What percentage of the given chemical is there?</h3>
Mg + 1/2O₂ -------> MgO
We now want to know the percent composition of MgO in light of this reaction. Since the original reactants' and the product's mass are not provided, we can use the component's atomic weights to solve this problem.
Let's compute the molar mass of MgO since Mg has a molecular weight of 24.305 g/mol and O has a molecular weight of 15.999 g/mol:
molar mass of 
Now with this weight, let's see the percent composition of this compound:
Mg percentage =
%
O percentage = 
%
The Percent composition of MgO is 60.304 % and 39.696 % respectively.
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Answer:
I would say that it is the bond called complementary hydrogen bonds
Explanation:
The nucleotides in a base pair are complementary which means their shape allows them to bond together with hydrogen bonds. The A-T pair forms two hydrogen bonds. The C-G pair forms three. The hydrogen bonding between complementary bases holds the two strands of DNA together.
Answer:
Detail is given below
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.
In A we can see that there is one positive charge and force of attraction is 2.30×10⁻⁸ N and distance is 0.10 nm
In B we can see that negative charge is further away from nucleus because of greater distance thus force of attraction will be less. 0.58×10⁻⁸ N
In C this distance further increases and force also goes in decreasing 0.26×10⁻⁸ N.
Answer:
hope it's helpful to you .
your 9th question is wrong but I did it correctly
it's not BaS2 it's BaS
