Answer:
B
Explanation:
Cuz they are supported once discovered and then widely spread then accepted
First, we have to get how many grams of C & H & O in the compound:
- the mass of C on CO2 = mass of CO2*molar mass of C /molar mass of CO2
= 0.5213 * 12 / 44 = 0.142 g
- the mass of H atom on H2O = mass of H2O*molar mass of H / molar mass of H2O
=0.2835 * 2 / 18 = 0.0315 g
- the mass of O = the total mass - the mass of C atom - the mass of H atom
= 0.3 - 0.142 - 0.0315 = 0.1265 g
Convert the mass to mole by divided by molar mass
C(0.142/12) H(0.0315/2) O(0.1265/16)
C(0.0118) H(0.01575) O(0.0079) by dividing by the smallest value 0.0079
C1.504 H3.99 O1 by rounding to the nearst fraction
C3/2 H4/1 )1/1 multiply by 2
∴ the emprical formula C3H8O2
The best description of the process to draw the segment is B. b place a compass at one endpoint of the segment and trace an arc. do the same from the other endpoint. draw a line through the intersections of the arcs.
<h3>What is a segment bisector?</h3>
It should be noted that a segment bisector simply means a line to segment which cuts another line segment at the center but dividing the lines into two equal halves.
In this case, based on the information given, the best description of the process to draw the segment is to place a compass at one endpoint of the segment and trace an arc, do the same from the other endpoint. draw a line through the intersections of the arcs.
In conclusion, the correct option is B.
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Answer: potassium iodide is the basic test for starch,and the positive test is blue-black coloration, any other test substance which is not starch will give a negative results.
Explanation:
Starch is an example of polysaccharide and since the standard test for it is potassium iodide solution, it gives a positive test.
Diasaccharides e.g maltose are reducing sugars.their standard test is BENEDICT test .
Therefore, in the hydrolysis; starch should give a positve test, while Diasaccharides should give negative rest.