Answer:
η = 40 %
Explanation:
Given that
Qa ,Heat addition= 1000 J
Qr,Heat rejection= 600 J
Work done ,W= 400 J
We know that ,efficiency of a engine given as
Now by putting the values in the above equation ,then we get
η = 0.4
The efficiency in percentage is given as
η = 0.4 x 100 %
η = 40 %
Therefore the answer will be 40%.
Answer:
The current through the resistor is 0.5 A
Explanation:
Given;
power of the light bulb = 60 W
voltage in the wall outlet across the plug terminals = 120 V
power of the light bulb is the product of voltage in the wall outlet across the plug terminals and the current passing through the resistor.
power = voltage x current
Therefore, for a 60 W light bulb powered by a connection to a wall outlet with 120 V across the plug terminals, the current passing through the resistor is 0.5 A