Answer:
60.9 metric tons of Mn are accumulated
Explanation:
The Mn accumulates at a rate of 0.06 mgm⁻²day⁻¹.
After 5.0years (5years * 365 = 1825days) will be accumulate:
0.06 mgm⁻²day⁻¹ * 1825 days =
109.5mgm⁻²
Now, 556km² are:
556 km² * ((1000m)² / 1km) = 5.56x10⁸ m²
In 5.56x10⁸ m² you will accumulate:
5.56x10⁸ m² * 109.5mgm⁻² = 6.09x10¹⁰mg are accumulated.
In kg:
6.09x10¹⁰mg * (1kg / 1x10⁶mg) = 6.09x10⁴kg.
In metric tons:
6.09x10⁴kg * (1 metric ton / 1000kg) =
<h3>60.9 metric tons of Mn are accumulated</h3>
Answer:
2,1,-1
Explanation:
The electronic configuration of oxygen is
The valence electrons are in the second principle quantum number, which means that the value of n = 2.
For, n =2,
l can be 0 or 1 which corresponds to s and p orbital respectively.
If l = 1 , which is p orbitals and it exits in 3 degenerate orbitals which has values of m = -1 , 0 , +1
<u>So, The possible set pf quantum number for the outermost valence electron of the oxygen atom is 2, 1, -1.</u>
Answer:Moseley used atomic number of an element and not the atomic mass unlike Mendeleev
3 plus 1 half = 3 and a half, which he does in a hour. 3.5 mph. Happy to help :D