Answer:
4.266 m.
Explanation:
Given,
Speed of the electron = 7.50 x 10⁶ m/s
Magnetic field, B = 1 x 10⁻⁵ T
radius of circular path = ?
Using formula of radius of curvature of the charge particle
m is mass of electron
q is charge of electron
r = 4.266 m
Hence, radius of circular path is equal to 4.266 m.
786Ω and 20.32Ω respectively.
<h2>Explanation:</h2>(a) Given a number of resistors each with its own resistance, the largest resistance can be obtained when these resistors are connected in series.
From the question, the resistors have the following resistances;
36.0-Ω, 50.0-Ω , and 700-Ω
Now, when they are connected in series, the total resistance (R) obtainable is given by the sum of these individual resistances as follows;
R = 36.0-Ω + 50.0-Ω + 700-Ω
R = 786Ω
Therefore, the largest resistance that can be obtained by connecting a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together is 786Ω
(b) Similarly, given a number of resistors each with its own resistance, the smallest resistance can be obtained when these resistors are connected in parallel.
From the question, the resistors have the following resistances;
36.0-Ω, 50.0-Ω , and 700-Ω
Now, when they are connected in parallel, the total resistance (R) obtainable is given by using the relation as follows;
=
+
+
=
=
=
R =
R = 20.32Ω
Therefore, the smallest resistance that can be obtained by connecting a 36.0-Ω , a 50.0-Ω , and a 700-Ω resistor together is 20.32Ω