Question

Um bloco de prata de massa m= 40g é aquecido de 30°C até 80° C

Answer 1

Answer:

a) Q = 111.6 cal

b) T2 = 415.15K = 142°C

Explanation:

a) To calculate the amount oh heat given to the block of silver, you use the following formula:

$Q=mc(T_2-T_1)$      (1)

m: mass of the block = 40g

T2: final temperature = 80°C = 353.15k

T1: initial temperature = 30°C = 303.25K

c: specific heat of silver = 0.0558cal/g.K

You replace the values of the parameters in the equation (1):

$Q=(40g)(0.0558cal/g.K)(353.15K-303.15K)=111.6\ cal$

hence, the amount of heat is 111.6 cal

b) The temperature is calculated by solving the equation (1) for T2:

$T_2=\frac{Q}{mc}+T_1\\\\T_2=\frac{250cal}{(40g)(0.0558cal/g.K)}+303.15K=415.15K$

hence, the final temperature when 250 cal of heat is geiven to the block of silver, is 415.15K