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jok3333 [9.3K]
3 years ago
9

An object is moving with an initial velocity of 3.3 m/s. It is then subject to a constant acceleration of 3.7 m/s2 for 10 s. How

far will it have traveled during the time of its acceleration?
I also need the complete Formula (Nothing left out)
Physics
1 answer:
Llana [10]3 years ago
5 0

Answer:

Explanation:

s = s₀ + v₀t + ½at²

ASSUMING the acceleration is in the direction of initial motion.

s = 0 + 3.3(10) = ½(3.7)(10²)

s = 218 m

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mr Goodwill [35]
<h3><u>Answer</u>;</h3>

$347.22

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Answer:

The angle between the red and blue light is 1.7°.

Explanation:

Given that,

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Wavelength of blue = 486 nm

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n_{r}=1.572

n_{b}=1.587

We need to calculate the angle for red wavelength

Using Snell's law,

n_{r}\sin\theta_{i}=n_{a}\sin\theta_{r}

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\theta_{r}=\sin^{-1}(\dfrac{1.572\sin37}{1})

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We need to calculate the angle for blue wavelength

Using Snell's law,

n_{b}\sin\theta_{i}=n_{a}\sin\theta_{b}

Put the value into the formula

1.587\sin37=1\times\sin\theta_{b}

\theta_{b}=\sin^{-1}(\dfrac{1.587\sin37}{1})

\theta_{b}=72.7^{\circ}

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\Delta \theta=\theta_{b}-\theta_{r}

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Answer:

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