A car moves with a speed of 30 metres per second calculate the distance travelled in 30 seconds

A roller coaster track is 3000 meters long. It takes 100 seconds to travel once around the roller coaster. What is the average s

Svetllana [295]

All you have to do is divide 3000 by 100, Its 30

6 0

3 years ago

Read 2 more answers

Two wheels with fixed hubs and radii 0.51 m and 1.9 m, each having a mass of 3 kg, start from rest. Forces 5 N and F2 are applie

Katarina [22]

Answer:

18.63 N

Explanation:

Assuming that the sum of torques are equal

Στ = Iα

First wheel

Στ = 5 * 0.51 = 3 * (0.51)² * α

On making α subject of formula, we have

α = 2.55 / 0.7803

α = 3.27

If we make the α of each one equal to each other so that

5 / (3 * 0.51) = F2 / (3 * 1.9)

solve for F2 by making F2 the subject of the formula, we have

F2 = (3 * 1.9 * 5) / (3 * 0.51)

F2 = 28.5 / 1.53

F2 = 18.63 N

Therefore, the force F2 has to 18.63 N in order to impart the same angular acceleration to each wheel.

3 0

3 years ago

Assume that at sea-level the air pressure is 1.0 atm and the air density is 1.3 kg/m3.

scoundrel [369]

Answer

Pressure, P = 1 atm

air density, ρ = 1.3 kg/m³

a) height of the atmosphere when the density is constant

Pressure at sea level = 1 atm = 101300 Pa

we know

P = ρ g h

$h = \dfrac{P}{\rho\ g}$

$h = \dfrac{101300}{1.3\times 9.8}$

h = 7951.33 m

height of the atmosphere will be equal to 7951.33 m

b) when air density decreased linearly to zero.

at x = 0 air density = 0

at x= h ρ_l = ρ_sl

assuming density is zero at x - distance

$\rho_x = \dfrac{\rho_{sl}}{h}\times x$

now, Pressure at depth x

$dP = \rho_x g dx$

$dP = \dfrac{\rho_{sl}}{h}\times x g dx$

integrating both side

$P = g\dfrac{\rho_{sl}}{h}\times \int_0^h x dx$

$P =\dfrac{\rho_{sl}\times g h}{2}$

now,

$h=\dfrac{2P}{\rho_{sl}\times g}$

$h=\dfrac{2\times 101300}{1.3\times 9.8}$

h = 15902.67 m

height of the atmosphere is equal to 15902.67 m.

6 0

2 years ago

Mark all the fermions a) Proton b) Electron c)Anti-top d) Gluon e) Tau Neutrino

aliya0001 [1]

Answer:

(a) Proton, (b) Electron (c) tau neutrino.

Explanation:

Elementary particles are the particles without any sub-structure which means they are not composed of other particles.

The elementary particles are classified into three categories which are discussed below:

(1) Quarks: up, down, top, bottom, strange, and charm.

(2) Leptons: electrons, electron neutrino, muon, muon neutrino, tau, tau neutrino.

(3) Bosons: Guon, photons Z bosons, W bosons, Higgs.

Fermions are particles that follow Fermi-Dirac statistics. Fermions consist of all the quarks and leptons. And fermions can also be categorized in elementary particles such as electrons and protons.

Therefore, the fermions in the given question are proton, electron, and tau neutrino.

5 0

3 years ago

How much work done when .0080 C is moved through a potential difference of 1.5 V? Use W = qV. A.

grin007 [14]

Answer:

0.012 J

Explanation:

We are given:

q = 0.0080C

Potential difference = 1.5V

W=qV

Substituting the values into the equation:

W=0.0080*1.5= 0.012J

8 0

3 years ago