Answer:
Flow rate 2.34 m3/s
Diameter 0.754 m
Explanation:
Assuming steady flow, the volume flow rate along the pipe will always be constant, and equals to the product of flow speed and cross-section area.
The area at the well head is
So the volume flow rate along the pipe is
We can use the similar logic to find the cross-section area at the refinery
The radius of the pipe at the refinery is:
So the diameter is twice the radius = 0.38*2 = 0.754m
As we know that in order to melt the copper we need to take the temperature of copper to its melting point
So here heat required to raise the temperature of copper is given as
We know that
melting temperature of copper = 1085 degree C
Specific heat capacity of copper = 385 J/kg C
now we have
now in order to melt the copper we know the heat required is
here we know that
L = 205 kJ/kg
now from above formula
now total heat required will be
As we know that
now we have