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NeTakaya
4 years ago
9

. Which of the following would be the best technique to use in order to separate an insoluble solid from a liquid?. Answer. . ch

romatography. . evaporation. . filtration. . simple distillation.
Physics
2 answers:
kvasek [131]4 years ago
8 0
The best technique to separate an insoluble solid from a liquid is filtration. Filtration is a process that separates solids from liquid by adding a medium, such as a filter paper, that only liquid can pass, and what is left behind the filter paper is the insoluble solid.
wlad13 [49]4 years ago
7 0

Answer:

filteration

Explanation:

i just did this and got it right

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A point on the end of a tuning fork moves in simple harmonic motion described by d = a sin ωt. Find ω given that the tuning fork
pantera1 [17]

Answer:

1609.1429 rad/sec

Explanation:

By using the relation Angular velocity and frequency as:

Angular velocity (ω) = 2×π×Frequency (ν)

Given the frequency = 256 vibrations per second.

So, Angular velocity can be calculated by using the above formula as:

Angular velocity (ω) = 2×π×Frequency (ν)

⇒Angular velocity (ω) = 2×π×256 rad/ sec

⇒Angular velocity (ω) = 2×(22/7)×256 rad/ sec

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Suppose a 32-kg child sits in a playground swing
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Explanation:

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Deep-focus earthquakes form at subduction zones as well as continental-continental plate boundaries True Or False
kipiarov [429]

Answer:

The answer is true, they can form at both.

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What is the term for the circular movement of material inside Earth's mantle?
Gala2k [10]

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5 0
3 years ago
You observe a hockey puck of mass 0.12 kg, traveling across the ice at speed 18.3 m/sec. The interaction of the puck and the ice
Galina-37 [17]

The stopping distance is 143.1 m

Explanation:

First of all, we have to find the acceleration of the hockey puck. This can be done by using Newton's second law of motion:

\sum F =ma

where

\sum F = F_f = -0.14 N is the net force acting on the puck (the force of friction, negative because it acts in a direction opposite to the direction of motion)

m = 0.12 kg is the mass of the puck

a is the acceleration

Solving for a,

a=\frac{\sum F}{m}=\frac{-0.14}{0.12}=-1.17 m/s^2

The motion of the puck is a uniformly accelerated motion, therefore we can use the following suvat equation:

v^2-u^2=2as

where:

v = 0 is the final velocity (the puck comes to a stop)

u = 18.3 m/s is the initial velocity

a=-1.17 m/s^2 is the acceleration

s is the stopping distance

And solving for s, we find

s=\frac{v^2-u^2}{2a}=\frac{0-(18.3)^2}{2(-1.17)}=143.1 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0
3 years ago
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