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NeTakaya
3 years ago
9

. Which of the following would be the best technique to use in order to separate an insoluble solid from a liquid?. Answer. . ch

romatography. . evaporation. . filtration. . simple distillation.
Physics
2 answers:
kvasek [131]3 years ago
8 0
The best technique to separate an insoluble solid from a liquid is filtration. Filtration is a process that separates solids from liquid by adding a medium, such as a filter paper, that only liquid can pass, and what is left behind the filter paper is the insoluble solid.
wlad13 [49]3 years ago
7 0

Answer:

filteration

Explanation:

i just did this and got it right

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zloy xaker [14]

PRETTY SURE ITS A AND C BUT I LOOKED IT UP AND IM ALMOST POSITIVE THARS IT

8 0
3 years ago
Read 2 more answers
Bohr found experimental evidence for his atomic model by studying _____.
nevsk [136]
For the answer to te question above, it is a. The Electron Cloud.
For additional information, The Electron Cloud is an informal term in physics. It is used to describe where electrons are when they go around the nucleus of an atom.
I hope my answer helped you.
6 0
3 years ago
Read 2 more answers
The uniform circular motion of a space station can be used to create artificial gravity. This can be done by adjusting the angul
DENIUS [597]

Answer:

The acceleration at the astronaut's head decreases.

Explanation:

Since the centripetal acceleration equals acceleration due to gravity,

a = g = GM/R². since a changes infinitesimally from his foot to his head, we differentiate a with respect to r to get da/dr = -2GM/R³.

So, da, the change in acceleration = -2GMdR/R³ = -2gdR/R = -2 × 9.8/6.4 × 10⁶ m =  -3.0625 × 10⁻⁶dR m/s².

Since dR = height of astronaut = 1.80 m, da = -3.0625 × 10⁻⁶ × 1.8 = -5.5125 × 10⁻⁶ m/s².

So the acceleration at the astronaut's head is g + da = 9.8 - 0.0000055125 = 9.7999944875 m/s².

So the acceleration at the astronaut's head decreases.

3 0
3 years ago
To determine the coefficient of static friction between two materials, an engineer places a small sample of one material on a ho
Fudgin [204]

This question is incomplete, the missing image is uploaded along this answer.

Answer:

the coefficient of friction is 0.32

Explanation:

 Given the data in the question;

we make use of kinematic equation of motion;

ω = ω₀ + ∝t

we substitute

ω = ( 0 rad/s ) + ( 0.4 rad/s² )( 9.903 s )

ω = 3.9612 rad/s

The centripetal force acting on the sample is;

Fc = mrω²

from the image; r = 200 mm = 0.2 m

so we substitute

Fc = m(0.2 m ) ( 3.9612 rad/s )²

Fc = (3.13822 m/s²)m

we know that the frictional force between the two materials should be providing the necessary centripetal force to rotate the sample object;

f = Fc

μN = Fc

μmg = (3.13822 m/s²)m

μ = (3.13822 m/s²)m / mg

μ = (3.13822 m/s²) / g

acceleration due to gravity g = 9.8 m/s²

so

μ = (3.13822 m/s²) / 9.8 m/s²

μ = 0.32

Therefore, the coefficient of friction is 0.32

5 0
3 years ago
Which term describes the image of an object located between a concave mirror and its focal point?
labwork [276]
Answer: I think it is b.
6 0
3 years ago
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