Answer:
I hope this answer is correct
Explanation:
Difference Between Gravitation and Gravity
Gravitation is referred to the force acting between two bodies which can be represented as the F=(GM1M2)/R2 which means gravitation force is proportional to the product of the masses of the object 1 and object 2 and is inversely proportional to the square of the distance between them. The gravitational force between earth and any object is known as gravity.
Difference Between Gravitation and Gravity
Gravitation Gravity
It is a universal force It is not a universal force
It is a weak force It is a strong force
The force is F=(GM1M2)/R2 (G= gravitational constant) The force is F=mg (g=acceleration due to gravity)
The direction of gravitational force lies in the radial direction from the masses The direction of the force of gravity is along the line joining the earth’s center and the center of the body. Its direction is towards the center of the earth.
The force can be 0 when the separation between bodies is infinity The force of gravity can be 0 at the center of the earth
It requires two masses It requires only one mass
These were some difference between Gravitation and Gravity. If you wish to find out more, download BYJU’S The Learning App.
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Gravity Acceleration Due to Gravity
Answer:
a) v₃ = 19.54 km, b) 70.2º north-west
Explanation:
This is a vector exercise, the best way to solve it is finding the components of each vector and doing the addition
vector 1 moves 26 km northeast
let's use trigonometry to find its components
cos 45 = x₁ / V₁
sin 45 = y₁ / V₁
x₁ = v₁ cos 45
y₁ = v₁ sin 45
x₁ = 26 cos 45
y₁ = 26 sin 45
x₁ = 18.38 km
y₁ = 18.38 km
Vector 2 moves 45 km north
y₂ = 45 km
Unknown 3 vector
x3 =?
y3 =?
Vector Resulting 70 km north of the starting point
R_y = 70 km
we make the sum on each axis
X axis
Rₓ = x₁ + x₃
x₃ = Rₓ -x₁
x₃ = 0 - 18.38
x₃ = -18.38 km
Y Axis
R_y = y₁ + y₂ + y₃
y₃ = R_y - y₁ -y₂
y₃ = 70 -18.38 - 45
y₃ = 6.62 km
the vector of the third leg of the journey is
v₃ = (-18.38 i ^ +6.62 j^ ) km
let's use the Pythagorean theorem to find the length
v₃ = √ (18.38² + 6.62²)
v₃ = 19.54 km
to find the angle let's use trigonometry
tan θ = y₃ / x₃
θ = tan⁻¹ (y₃ / x₃)
θ = tan⁻¹ (6.62 / (- 18.38))
θ = -19.8º
with respect to the x axis, if we measure this angle from the positive side of the x axis it is
θ’= 180 -19.8
θ’= 160.19º
I mean the address is
θ’’ = 90-19.8
θ = 70.2º
70.2º north-west
I am not so sure about this it is too difficult
