Answer:
Heat transfer in the process is -19.6 kJ
Work done in the process is - 28 kJ
Explanation:
As we know that the process equation is given as
now we know that
now from above equation we have
now work done in this process is given as
here we know N = 1.1
so we have
Now we have
now we have
so we have
Very slightly less than 1 g/cm^3 averaged over the entire body.
Even though it doesn't feel like it when you're in the pool, if you completely relax and let go, you do float in water.
<h2>
The car tire makes 149 revolutions before coming to stop.</h2>
Explanation:
a) We have equation of motion v² = u² + 2as
Initial velocity, u = 32.4 m/s
Acceleration, a = -1.70 m/s²
Final velocity, v = 0 m/s
Substituting
v² = u² + 2as
0² = 32.4² + 2 x -1.70 x s
s = 308.75 m
Distance traveled before stopping is 308.75 m
Radius of tire = 0.330 m
Circumference of tire = 2πx 0.33 = 2.07 m
1 revolution = 2.07 m
The car tire makes 149 revolutions before coming to stop.
Ez the answer to your question would be
(-4) cecause I am super smart ? 931
<h2>
a) Volume of anchor is 0.019 m³</h2><h2>
b) Weight of anchor in air is 1463.17 N</h2>
Explanation:
a) Weight loss in water = Volume of object x density of water x acceleration due to gravity
183 = Volume of anchor x 1000 x 9.81
Volume of anchor = 0.019 m³
b) Weight = Mass x acceleration due to gravity = Volume x Density x acceleration due to gravity
Weight of anchor in air = Volume of anchor x Density of anchor x acceleration due to gravity
Weight of anchor in air = 0.019 x 7850 x 9.81 = 1463.17 N
Weight of anchor in air = 1463.17 N