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Minchanka [31]
4 years ago
14

How does the map scale help to interpret the map?

Engineering
2 answers:
krok68 [10]4 years ago
6 0

Map scale refers to the relationship (or ratio) between distance on a map and the corresponding distance on the ground. For example, on a 1:100000 scale map, 1cm on the map equals 1km on the ground.

blondinia [14]4 years ago
6 0

Answer:

c

Explanation:

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The A-36 steel pipe has a 6061-T6 aluminum core. It issubjected to a tensile force of 200 kN. Determine the averagenormal stress
sasho [114]

Answer:

In the steel: 815 kPa

In the aluminum: 270 kPa

Explanation:

The steel pipe will have a section of:

A1 = π/4 * (D^2 - d^2)

A1 = π/4 * (0.8^2 - 0.7^2) = 0.1178 m^2

The aluminum core:

A2 = π/4 * d^2

A2 = π/4 * 0.7^2 = 0.3848 m^2

The parts will have a certain stiffness:

k = E * A/l

We don't know their length, so we can consider this as stiffness per unit of length

k = E * A

For the steel pipe:

E = 210 GPa (for steel)

k1 = 210*10^9 * 0.1178 = 2.47*10^10 N

For the aluminum:

E = 70 GPa

k2 = 70*10^9 * 0.3848 = 2.69*10^10 N

Hooke's law:

Δd = f / k

Since we are using stiffness per unit of length we use stretching per unit of length:

ε = f / k

When the force is distributed between both materials will stretch the same length:

f = f1 + f2

f1 / k1 = f2/ k2

Replacing:

f1 = f - f2

(f - f2) / k1 = f2 / k2

f/k1 - f2/k1 = f2/k2

f/k1 = f2 * (1/k2 + 1/k1)

f2 = (f/k1) / (1/k2 + 1/k1)

f2 = (200000/2.47*10^10) / (1/2.69*10^10 + 1/2.47*10^10) = 104000 N = 104 KN

f1 = 200 - 104 = 96 kN

Then we calculate the stresses:

σ1 = f1/A1 = 96000 / 0.1178 = 815000 Pa = 815 kPa

σ2 = f2/A2 = 104000 / 0.3848 = 270000 Pa = 270 kPa

5 0
3 years ago
The typical measurement of hotel demand is the room night (RN). When we say that each room night is perishable , we mean that on
Marta_Voda [28]

Answer:

Yes once a room is not rented for a couple of hours in the night then it is perishable.

8 0
3 years ago
You are given a collection of n bottles of different widths and n lids of different widths and you need to find which lid goes w
Sladkaya [172]

Answer:

void bubble_sort( int A[ ], int n ) {

     int temp;

     for(int k = 0; k< n-1; k++) {

          // (n-k-1) to ignore comparisons of already compared iterations

         for(int i = 0; i < n-k-1; i++) {

                 if(A[ i ] > A[ i+1] ) {

                      // swapping occurs here

                      temp = A[ i ];

                      A[ i ] = A[ i+1 ];

                      A[ i + 1] = temp ;

                  }

          }

    }

}

5 0
3 years ago
: A freeway exit ramp has a single lane and consist of entirely of a horizontal curve with a central angle of 90 degree and a le
Mariana [72]

The design speed was used for the freeway exit ramp is 11 mph.

<h3>Design speed used in the exit ramp</h3>

The design speed used in the exit ramp is calculated as follows;

f = v²/15R - 0.01e

where;

  • v is designated speed

v = ωr

v = (θ/t) r

θ = 90⁰ = 1.57 rad

v = (1.57 x 19.4)/2.5 s

v = 12.18 ft/s = 8.3 mph

<h3>Design speed</h3>

f = v²/15R - 0.01e

let the maximum superelevation, e = 1%

f = (8.3)²/(15 x 19.4) - 0.01

f = 0.22

0.22 is less than value of f which is 0.4

<h3>next iteration, try 10 mph</h3>

f = (10)²/(15 x 19.4) - 0.01

f = 0.33

0.33 is less than 0.4

<h3>next iteration, try 11 mph</h3>

f = (11)²/(15 x 19.4) - 0.01

f = 0.4

Thus, the design speed was used for the freeway exit ramp is 11 mph.

Learn more about design speed here: brainly.com/question/22279858

#SPJ1

4 0
2 years ago
At what depth in water is the increased pressure five times greater than atmospheric pressure (101 kPa)?​
umka21 [38]

Explanation:

40.4m

Explanation:

Pressure at depth is given as

P = P, + pgh

Final pressure at depth h= 5 Po

5Po= Po + pgh

pgh = 4Po = 4 x 1.01 x 10^5

h = (4.04×10^5)/ (1000x10)

h=40.4m

8 0
3 years ago
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