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Aleksandr-060686 [28]
2 years ago
8

Help with this question

Physics
1 answer:
Alina [70]2 years ago
3 0

Answer:

D and B.

Explanation:

The wavelength must be taken from the same corresponding point. D and B are both at the crests of a wave, with no other crests in between, which means the distance between them is equal to one wavelength.

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Which equation can correctly express the relation between force, acceleration, and mass?
Roman55 [17]

Hi there!

\large\boxed{\text{a) F = m * a}}

According to Newton's Second Law, force is calculated with the formula:

F = m × a, where:

F = force (N)

m = mass (kg)

a = acceleration (m/s²)

7 0
3 years ago
Read 2 more answers
If a Ferrari, with an initial velocity of 10 m/s,
soldier1979 [14.2K]
<em>Acceleration at 50m/sec² :  means every second the velocity increases by 50 m/sec. In 3 seconds the velocity increases by 150 m/s. So total will be 160 m/sec.

the formula is
</em>

<em>  V = final velocity  =  U initial velocity + acceleration a * time duration t</em>

<em>  V = 10 m/s + 50 m/sec² * 3 sec  =  160 m/sec</em>

6 0
3 years ago
A body moving in the positive x direction passes the origin at time t = 0. Between t=0 and t=1 second, the body has a constant s
lord [1]

The important thing in this type of questions is to keep track of what you are doing at every point.

From t=0 to t=1s, there is uniform motion at v=24 m/s.

Therefore, it will move 24m in that second of time.

Afterwards, an acceleration comes in, so from t=1s to 11s there will be uniformly accelerated motion with acceleration -6m/s^2.

To account for this, you need to use Suvat's equation:

x(t)=x0+v0*t+1/2*a*t^2.

You should know what to plug in for each of the symbols in this equation:

x0 [initial position at t=1s] = 24m

v0 [initial velocity at t=1s] = 24 m/s

a [acceleration, switched on at t=1s] = -6 m/s^2

t [time from the start of the acceleration until the end, i.e. from t=1s to t=11s] = 10s

Plugging in those numbers in the equation will give you the position at t=11s.

4 0
3 years ago
Read 2 more answers
Followed by the previous question: presume that the electron performs a uniform circular motion around the hydrogen nucleus. Wha
Ksivusya [100]

Answer:

A_c=87.73*10^{21}m/s

Explanation:

From the question we are told that

r=5\times 10^{-11}

T=1.5 \times 10^{-16}

Generally the equation for velocity is mathematically given as

Velocity (v)=\frac{2 \pi r}{t}

V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}

V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}

Generally the equation for Centripetal acceleration is mathematically given as

A_c=\frac{V^2}{r}

A_c=(\frac{20.944*10^5)}{r5*10^{-11}}

A_c=87.73*10^{21}m/s

8 0
3 years ago
How does a machine, such as a ramp, help make work easier?
Dovator [93]

Answer:

D

A machine can help decrease the input force and increase the output force.

6 0
2 years ago
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