Answers:
a) 
b) 
c) 
d) 46000 s
Explanation:
<h2>a) Time for one cycle of the radio wave</h2>
We know the maser radiowave has a frequency 
of 
In addition we know there is an inverse relation between frequency and time 
:
(1)
Isolating : 
(2)
(3)
(4) This is the time for 1 cycle
<h2>
b) Cycles that occur in 1 h</h2>
If 
and we already know the amount of cycles per second , then:
This is the number of cycles in an hour
<h2>c) How many cycles would have occurred during the age of the earth, which is estimated to be
?</h2>
Firstly, we have to convert this from years to seconds:
Now we have to multiply this value for the frequency of the maser radiowave:
This is the number of cycles in the age of the Earth
<h2>
d) By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth?</h2>
If we have 1 second out for every 100,000 years, then:
This means the maser would be 46000 s off after a time interval equal to the age of the earth
Answer:
x coordinate = -1.66 m
y coordinate is = -0.825m
Explanation:
Suppose z be the distance form the first charge and z + sqrt(1^2 +.5^2) be the distance from the second So z + sqrt(1+.25) = z + 1.12
We have k*2.0x10^-6/s^2 = k*6x10^-6/(s+1.12)^2
0.0356s^2 -0.019s-0.0897=0
s=1.876m
The angle of the line between the two charges is arctan(.5/1) = 26.6o
x coordinate = -1.876*cos(26.6) = -1.66m
y coordinate is -1.876*sin(26.6) = -0.825m
Friction is the correct answer.
In order to solve this problem it is necessary to apply the concepts related to intensity and specifically described in Malus's law.
Malus's law warns that
Where,
Angle between the analyzer axis and the polarization axis
Intensity of the light before passing through the polarizer
The intensity of the beam from the first polarizer is equal to the half of the initial intensity
Replacing with our the numerical values we get
Therefore the intensity of the light that emerges from the filter is 
Answer:
Explanation:
Using the atomic mass of pluonium atoms (244 g/mol), you can calculate the number of atoms in 47.0 g. Then, knowing that each plutonium atom has 96 protons, you calculate the number of protons in the 47.0 g sample. Finally, using the positive charge of one proton, you calculate the total positive charge in the 47.0 g of plutonium.
<u>1. Number of atoms of plutonium in 47.0 g</u>
- Number of moles = mass / atomic mass = 47.0 g / 244 = 0.1926 moles
- Number of atoms = number of moles × 6.022 × 10²³ atoms/mol
- Number of atoms = 0.1926 mol × 6.022 × 10²³ atoms/mol = 1.15998×10²³ atoms
<u>2. Number of protons</u>
- Number of protons = 1.15998×10²³ atoms × 96 protons/atom = 1.11385×10²⁵ protons
<u>3. Charge</u>
<u />
- Charge = charge of one proton × number of protons
- Charge = 1.602×10⁻¹⁹ C/proton × 1.11385×10²⁵ protons = 1.78×10⁶C
