Question

The total number of atoms represented by the formula k3fe(cn)6 is:

Answer 1

Answer : The total number of atoms represented by the formula $K_3Fe(CN)_6$ is, $96.3\times 10^{23}$

Explanation :

The given compound is, $K_3Fe(CN)_6$

In the given compound, there are three moles of potassium (K) atoms, one moles of iron (Fe) atom, six moles of carbon (C) atoms and six moles of nitrogen (N) atoms.

Thus, the total moles of $K_3Fe(CN)_6$ = 3 + 1 + 6 + 6 = 16

As we know that,

1 mole contains $6.022\times 10^{23}$ number of atoms.

So, 16 moles contains $16\times 6.022\times 10^{23}=96.3\times 10^{23}$ number of atoms.

Therefore, the total number of atoms represented by the formula $K_3Fe(CN)_6$ is, $96.3\times 10^{23}$

Answer 2

K3Fe(CN)6

K - 3 atoms
Fe - 1 atom
C - 6 atoms
N - 6 atoms

Altogether : 3+1+6+6= 16 atoms