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2 years ago

I want help with these questions thanks !

Chemistry

1 answer:

Studentka2010 [4]2 years ago

5 0

Answer:

I will give you hints, as follows:

Explanation:

- two words: climate change

- methane smells funny

- the number of electric cars sold each year is increasing

- there´s a reason they´re call "renewable"

- GEOmetry, GEOlogy, GEOthermal

Hope this helps!

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Which of the following is a balanced equation for the reaction described below?

mylen [45]

The correct answer is b

5 0

3 years ago

1.50μm2. Convert this to square meters.

mars1129 [50]

Based on the standards of units conversion, to convert from micrometer to meter, we multiply by 10^-6.
Since we there is a square (10^2) to consider, then to convert from micrometer squared to meter squared, we will multiply by (10^-6)^2 as follows:
1.5 <span>μm2 = 1.5 x (10^-6)^2 = 1.5 x 10^-12 meter sqaures</span>

6 0

3 years ago

A magnesium (Mg) atom gives one electron to two atoms of another element, then it takes on a 2+ charge. The two atoms of the oth

Setler [38]

Answer:

See below

Explanation:

You missed the following elements, but any element with 7 valence electrons could behave like that: Cl, Br, I, F, etc

3 0

3 years ago

Read 2 more answers

A 0.2121g sample of an organic compound was burned in a stream of oxygen and the carbon dioxide produced was collected in a stre

pav-90 [236]

Answer:

The answer to your question is: 17.26% of carbon

Explanation:

Data

CxHy = 0.2121 g

BaCO₃ = 0.6006 g

Molecular mass BaCO₃ = 137 + 12 + 48 = 197 g

Reaction

CO₂ + Ba(OH)₂ ⇒ BaCO₃ + H₂O

Process

1.- Find the amount of carbon in BaCO₃

197 g of BaCO₃ --------------- 12 g of Carbon

0.6006 g ---------------- x

x = (0.6006 x 12) / 197

x = 0.0366 g of carbon

2.- Calculate the percentage of carbon in the organic compound

0.2121 g of organic compound --------------- 100%

0.0366g -------------- x

x = (0.0366 x 100) / 0.2121

x = 17.26%

4 0

3 years ago

16.25 g of water at 54 C relaeases 402.7 J. What will be its final temp?

leonid [27]

Data:
Q = 402.7 J → releases → Q = - 402.7 J
m = 16.25 g
T initial = 54 ºC
adopting: c = 4.184J/g/°C
ΔT (T final - T initial) = ?

Solving:

Q = m*c*ΔT
-402.7 = 16.25*4.184*ΔT
-402.7 = 67.99*ΔT
$\Delta\:T = \frac{-402.7}{67.99}$
$\boxed{\Delta\:T \approx -5.92\:^0C}$

If: ΔT (T final - T initial) = ?
$-5.92^0 = T_{final} - 54^0$
$T_{final} = 54^0 - 5.92^0$
$\boxed{\boxed{T_{final} = 48.08\:^0C}}\end{array}}\qquad\quad\checkmark$

8 0

3 years ago

I want help with these questions thanks !​

I want help with these questions thanks !