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3 years ago

PLS HURRY THIS IS DUE TODAY!!!

Physics

2 answers:

loris [4]3 years ago

8 0

Answer:

B. between carbon and oxygen

Explanation:

formaldehyde has a carbon atom that has single bonds with two hydrogen atoms on both sides, and it has a double bond with oxygen.

baherus [9]3 years ago

7 0

Answer:

The placement of the double bond is between carbon atom and oxygen atom

this same question was for me so I did and got it correct

please mark me as brainliest

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Actinium-226 has a half-life of 29 hours. If 10g of actinium-226 disintegrates over a period of 145 hours,

Masteriza [31]

Answer: d) 312.5 mg

Explanation:

This problem can be solved using the Radioactive Half Life Formula:

$A=A_{o}.2^{\frac{-t}{h}}$

Where:

$A$ is the remaining amount of Actinium-226

$A_{o}=10 g$ is the initial amount of Actinium-226

$t=145 h$ is the time elapsed

$h=29 h$ is the half life of Actinium-226

Knowing this, let's find $A$ :

$A=(10 g) (2)^{\frac{-145 h}{29 h}}$

$A=0.3125 g \frac{1000 mg}{1 g}=312.5 mg$

4 0

4 years ago

You are on an airplane traveling 30° south of due west at 180 m/s with respect to the air. The air is moving with a speed 31 m/s

BlackZzzverrR [31]

1) 211m/s
2)240<span>°
3)759,600m or 759.6 km</span>

6 0

4 years ago

A camera phone called the iPhone X has an image sensor size of 5 mm and a focal length of 4 mm. How long of a selfie-stick must

azamat

Answer:

length of selfie-stick is 1.62 m

Explanation:

Given data

image size h1 = 5 mm = 5 × $10^{-3}$ m

focal length = 4 mm = 4 × $10^{-3}$ m

distance h2 = 2.032 m

to find out

How long of a selfie-stick

solution

here we find first magnification

that is M = h1 /h2

M = 5 × $10^{-3}$ / 2.032

M = 2.46 × $10^{-3}$

and we know M = p/q

so p = Mq = 2.46 × $10^{-3}$ q

so we apply lens formula

1/f = 1/p - 1/q

1/ 4 × $10^{-3}$ = 1 / 2.46 × $10^{-3}$ q - 1/q

q = 1.622 m

so length of selfie-stick is 1.62 m

4 0

3 years ago

Equations to use: v= λ ∙ f v=d/t

Margarita [4]

b. 460.8 m/s

Explanation:

The relationship between the speed of the wave along the string, the length of the string and the frequency of the note is

$f=\frac{v}{2L}$

where v is the speed of the wave, L is the length of the string and f is the frequency. Re-arranging the equation and substituting the data of the problem (L=0.90 m and f=256 Hz), we can find v:

$v=2Lf=2(0.90 m)(256 Hz)=460.8 m/s$

c. 18,000 m

Explanation:

The relationship between speed of the wave, distance travelled and time taken is

$v=\frac{d}{t}$

where

v = 6,000 m/s is the speed of the wave

d = ? is the distance travelled

t = 3 s is the time taken

Re-arranging the formula and substituting the numbers into it, we find:

$d=vt=(6,000 m/s)(3 s)=18,000 m$

3 0

3 years ago

an object moves 2.21 m in the + x-direction under the influence of a 114 N force directed 43 degrees above the x-axis. Find the

Nadusha1986 [10]

Work = Force * distance
= 114 N * 2.21m cos(43)
= 184.3 J

3 0

3 years ago