4 neutrons that are produced along with the Zn and sm. The complete final equation is: ²³⁵U + ¹n → 
+ 4 n
<h3>What atomic mass?</h3>
Atomic mass, the quantity of matter contained in an atom of an element.
1) In the left side of the transmutation equation appears:
²³⁵U + ¹n →
Deleting the atomic number (subscript to the left) because the question does not show them as it is focused on a number of neutrons.
2) The right side of the transmutation equation has:
→ +?
3) The total mass number of the left side is 235 + 1 = 236
4) The total mass number of Zn and sm on the right side is 160 + 72 = 232
5) Then, you are lacking 236 - 232 = 4 unit masses on the right side which are the 4 neutrons that are produced along with the Zn and sm.
The complete final equation is:
²³⁵U + ¹n → + 4 n
Learn more about the atomic mass here:
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Answer:Calculate The PH Of The Solution After The Addition Of The Following Amounts Of HCl. PLEASE HELP! SHOW ALL STEPS!! This problem has been solved!
Explanation:
Answer:
b. 2.28 M
Explanation:
The reaction of neutralization of NaOH with H2SO4 is:
2NaOH + H2SO4 → Na2SO4 + 2H2O
<em>Where 2 moles of NaOH react per mole of H2SO4</em>
<em />
To solve the concentration of NaOH we need to find the moles of H2SO4. Using the chemical equation we can find the moles of NaOH that react and with the volume the molar concentration as follows:
<em>Moles H2SO4:</em>
45.7mL = 0.0457L * (0.500mol/L) = 0.02285 moles H2SO4
<em>Moles NaOH:</em>
0.02285 moles H2SO4 * (2moles NaOH / 1 mol H2SO4) = 0.0457moles NaOH
<em>Molarity NaOH:</em>
0.0457moles NaOH / 0.020L =
2.28M
Right option:
<h3>b. 2.28 M</h3>
(2) 2 - 7 - 18 - 7 does, because the electron from the L shell jumped to the N shell, which requires energy.
The rest of them are either different types of atoms (different elements) or are not the excited state (ground state)
