Ask question

Ask question

All categories

2 years ago

8

Also, this one I have an answer but not rly sure so um help

1 answer:

mestny [16]2 years ago

7 0

Answer:

h(x) = - 2x² + 3

Step-by-step explanation:

Given f(x) then f(x) + c is a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Here the shift is 7 units up , then

h(x) = f(x) + 7 = - 2x² - 4 + 7 = - 2x² + 3

You might be interested in

Which number is composite 2, 5, 11, 9,

kykrilka [37]

Answer:

9

Step-by-step explanation:

3*3 =9

4 0

2 years ago

What is the length of D.<br> 8ft

KengaRu [80]

Answer:

96 inches

Step-by-step explanation:

8 ft is 8(12) inches, which is 96 inches

6 0

2 years ago

Find simple interest to the nearest cent for each principle, rate, and time. I= Prt. $1200, 3.9%, 2 years 6 months.

kykrilka [37]

Answer:

117.00

Step-by-step explanation:

I = prt where i is the interest , p is the principal r is the rate and t is the time in years

2 years 6 months is 2.5 years

I = 1200 * .039* 2.5

I =117

6 0

2 years ago

State the possible rational zeros and then factor each

Rom4ik [11]

All possible roots is the attachment
X=-1,-1/4,-4
Factor with the GCF 1

5 0

3 years ago

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

2 years ago