Answer: Magnesium Alloy
Explanation:
Cross sectional area A = (pi/4)d sqr
A = pi / 4 x 0.015 sqr
A = 1.76 x 10^-4 m2
Stressed induced in rod S = P/A = 35000/1.76x 10^-4
S= 198.06 M Pa
Reduction in diameter of the titanium alloy = -v (alpha/E) x d
= - 0.33 (( 198.06 X 10^6) / 70 x 10^9 )x 0.015 = - 1.41 x 10^-2 mm
For steel alloy
= - 0.36 (( 198.06 X 10^6) / 150 x 10^9 )x 0.015 = - 1.02 x 10^-2 mm
For magnesium
= 0.27 (( 198.06 X 10^6) / 205 x 10^9 )x 0.015 = 0.391 x 10^-2 mm
The titanium alloy and the steel alloy does not satisfy the second criteria since the reduction in diameter exceeds the allowable limit of 1.2 x 10^2mm
Considering the yield strength of the material, we find the aluminium alloy is not suitable and hence no need to check for the second criteria. By considering the both the given conditions, we find the magnesium alloy is the suitable material.
It is a well known fact that the ocean modifies the climate favorably so as to keep the ambient temperature warmer than it usually is inland away from the ocean so that is why the nightime drop in temperature will be less near the sea than inland.
Answer:
Aluminum hydrochloric acid
Explanation:
Aluminum reacts with diluted hydrochloric acid at room temperature. The metal aluminium dissolves in hydrochloric acid, producing aluminum chloride and colorless hydrogen gas. The reaction taking place between aluminium and hydrochloric acid is irreversible. And the final products will not react with each other.