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Alexandra [31]
2 years ago
15

A truck pushes a mound of dirt 5 meters with a force of 75 newtons. How much work has been done?

Physics
1 answer:
dem82 [27]2 years ago
3 0

Answer:

375\:\mathrm{N}

Explanation:

Work is given by the equation W=F\Delta x. Plugging in given values, we get:

W=75\cdot 5=\fbox{$ 375\:\mathrm{N}$}.

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If the total mechanical energy of the system is 100 J: Where does the pendulum have 100 J of kinetic energy? Where does the pend
Katena32 [7]

Answer:

See image and explanation

Explanation:

A simple pendulum consists of a string to which a bulb is attached and the string is tied to a support. The string swings from one end to the other as shown.

At the both ends, the energy of the pendulum is all potential. Hence we have 100J potential energy at both ends.

When the pendulum is in motion, the energy is all kinetic at the center of motion. Hence at that point, we have 100J kinetic energy.

In between both extremes the energy is both kinetic and potential as shown. The total energy is this a summation of the two.

6 0
3 years ago
Determine the amount of time for polonium-210 to decay to one fourth its original quantity. The half-life of polonium-210 is 138
ira [324]

Answer: 276 days

Explanation:

This problem can be solved using the Radioactive Half Life Formula:  

A=A_{o}.2^{\frac{-t}{h}} (1)  

Where:  

A=\frac{1}{4}A_{o} is the final amount of the material

A_{o} is the initial amount of the material  

t is the time elapsed  

h=138 days is the half life of polonium-210

Knowing this, let's substitute the values and find t from (1):

\frac{1}{4}A_{o}=A_{o}2^{\frac{-t}{138 days}} (2)  

\frac{A_{o}}{4A_{o}}=2^{\frac{-t}{138 days}} (3)  

\frac{1}{4}=2^{\frac{-t}{138 days}} (4)  

Applying natural logarithm in both sides:

ln(\frac{1}{4})=ln(2^{\frac{-t}{138 days}}) (5)  

-1.386=-\frac{t}{138days}ln(2) (6)  

Clearing t:

t=276days (7)  

7 0
3 years ago
Which feature forms most of the ocean floor. describe it in detail
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3 years ago
Which statement best describes the polarization of light
QveST [7]
The wave oscillates in a single plane. so the answer would be (c) i think
8 0
2 years ago
A circular loop of radius 11.9 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane
djverab [1.8K]

Answer:

(a). The strength of the magnetic field is 0.1933 T.

(b). The magnetic flux through the loop is zero.

Explanation:

Given that,

Radius = 11.9 cm

Magnetic flux \phi=8.60\times10^{-3}\ T m^2

(a). We need to calculate the strength of the magnetic field

Using formula of magnetic flux

\phi=BA\cos\theta

\phi=BA\cos0

\phi=BA

B=\dfrac{\phi}{A}

B=\dfrac{\phi}{\pi r^2}

Put the value into the formula

B=\dfrac{8.60\times10^{-3}}{\pi\times(11.9\times10^{-2})^2}

B=0.1933\ T

(b). If the magnetic field is directed parallel to the plane of the loop,

We need to calculate the magnetic flux through the loop

Using formula of flux

\phi=BA\cos\theta

Here, \theta=90^{\circ}

\phi=BA\cos90

\phi=0

Hence, (a). The strength of the magnetic field is 0.1933 T.

(b). The magnetic flux through the loop is zero.

3 0
3 years ago
Read 2 more answers
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