The volume of the room is the product of its dimensions:
Now, from the equation
where d is the density, m is the mass and V is the volume, we deduce
So, multiply the density and the volume to get the mass of air in the room.
Answer:
The marble as lost energy due to gravity, air resistance (if there is air), and the centripetal force when going around that loop.
Explanation:
Also a little in heat but that rly doesnt matter
Answer:
9.31%
Explanation:
We are given that
Mass of KBr=49.3 g
Volume of solution=473 mL
Density of solution =1.12g/mL
We have to find the mass% of KBr.
Mass =
Using the formula
Mass of solution=
Mass % of KBr=
Mass % of KBr=
Mass % of KBr=9.31%
Hence, the mass% of KBr=9.31%
Answer:
170 N
Explanation:
The following data were obtained from the question:
Mass (m) = 20 Kg
Angle (θ) = 30°
Acceleration due to gravity (g) = 9.8 m/s²
Weight (W) =?
The perpendicular component of the weight can be obtained by using the following formula:
W = mg × Cosθ
W = 20 × 9.8 × Cos 30
W = 196 × 0.866
W = 169.7 ≈ 170 N
Therefore, perpendicular component of the weight is 170 N
Answer:
work done = 117 kJ
Explanation:
given data
mass m = 3 kg
constant pressure P = 200 kPa
temperature T = 200°C
solution
we know that work done by steam is express as
work done = pressure × ΔVolume ....................1
and here ΔVolume = final volume - initial volume
we use here steam table and get at pressure 200 kPa
final specific volume = 1.08052 m³/kg
and
initial specific volume = 0.885735 m³/kg
so here
ΔV = 3 × (1.08052 - 0.885735)
ΔV = 0.584 m³
so put value in equation 1 we get
work done by steam = 200 × 0.584
work done = 117 kJ