It takes 13 cup of sugar to make a milkshake. You have 6 cups of sugar. How many milkshakes can you make?

Mathematics

1 answer:

Reika [66]4 years ago

4 0

Answer: 18

Step-by-step explanation:

Well is 18 because you just have to divide 6 and 1/3 and it will give you 18.

Hope it helps.

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50 POINTS! BRAINLIEST!!!

Anton [14]

The 1st choice (x - 9, y - 3) is the correct answer.

Take any of the corresponding coordinate points to find the rule that represents the translation:

D —> D’

(3, 5) —> (-6, 2)

(3 - 9, 5 - 3) = (-6, 2)

Counting the units from graph also shows this translation rule, seeing that hexagon DEFGHI moved 9 units to the left and 3 units down.

Hope this helps :)

5 0

4 years ago

Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t

Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

<h3>What is sequence ?</h3>

Sequence is collection of numbers with some pattern .

Given sequence

$a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20$

We can see that

$\frac{a_1}{a_2}=\frac{-10}{5}=-2\\$

and

$\frac{a_2}{a_3}=\frac{20}{-10}=-2\\$

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now $n^{th}$ term of this Geometric progression can be written as

$T_{n}= 5\times(-2)^{n-1}$

So summation of 15 terms can be written as

$\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is $\sum_{n=4}^{15} 5(-2)^{n-1}$$$

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0

3 years ago

A cylinder has a total volume of 678.59 and a height of 6m. what is the diameter of the cylinder? please help and show work

RoseWind [281]