The concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
- We'll begin by calculating the number of mole in 20.5 g of Zn(C₂H₃O₂)₂
Mass of Zn(C₂H₃O₂)₂ = 20.5 g
Molar mass of Zn(C₂H₃O₂)₂ = 65 + 2[(12×2) + (3×1) + (16×2)]
= 65 + 2[59]
= 183 g/mol
<h3>Mole of Zn(C₂H₃O₂)₂ =? </h3>
Mole = mass / molar mass
Mole of Zn(C₂H₃O₂)₂ = 20.5 / 183
<h3>Mole of Zn(C₂H₃O₂)₂ = 0.112 mole </h3>
- Finally, we shall determine concentration of Zn(C₂H₃O₂). This can be obtained as follow:
Mole of Zn(C₂H₃O₂)₂ = 0.112 mole
Volume = 105 mL = 105 / 1000 = 0.105 L
<h3>Concentration of Zn(C₂H₃O₂)₂ =? </h3>
Concentration = mole / Volume
Concentration of Zn(C₂H₃O₂)₂ = 0.112 / 0.105
<h3>Concentration of Zn(C₂H₃O₂)₂ = 1.067 M</h3>
Therefore, the concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
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