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kvv77 [185]
2 years ago
6

Consider the following chemical reaction.

Chemistry
1 answer:
Ede4ka [16]2 years ago
5 0

The concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M

  • We'll begin by calculating the number of mole in 20.5 g of Zn(C₂H₃O₂)₂

Mass of Zn(C₂H₃O₂)₂ = 20.5 g

Molar mass of Zn(C₂H₃O₂)₂ = 65 + 2[(12×2) + (3×1) + (16×2)]

= 65 + 2[59]

= 183 g/mol

<h3>Mole of Zn(C₂H₃O₂)₂ =? </h3>

Mole = mass / molar mass

Mole of Zn(C₂H₃O₂)₂ = 20.5 / 183

<h3>Mole of Zn(C₂H₃O₂)₂ = 0.112 mole </h3>

  • Finally, we shall determine concentration of Zn(C₂H₃O₂). This can be obtained as follow:

Mole of Zn(C₂H₃O₂)₂ = 0.112 mole

Volume = 105 mL = 105 / 1000 = 0.105 L

<h3>Concentration of Zn(C₂H₃O₂)₂ =? </h3>

Concentration = mole / Volume

Concentration of Zn(C₂H₃O₂)₂ = 0.112 / 0.105

<h3>Concentration of Zn(C₂H₃O₂)₂ = 1.067 M</h3>

Therefore, the concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M

Learn more: brainly.com/question/25511880

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