The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 1 x 10^6 <span>microliters (mL) in 1 L.
35 kL (1,000 L/ 1kL) (</span>1 x 10^6 microliters / 1 L) = 3.5 x 10^10 microliters<span>
The volume of this pond in microliters is </span><span>3.5 x 10^10 microliters</span>
Answer:
Number of moles = 3.82 mol
Explanation:
Given data:
Number of moles of CO₂ = ?
Mass of CO₂ = 168.2 g
Solution:
Number of moles = mass/molar mass
Molar mass of CO₂ = 44 g/mol
By putting values,
Number of moles = 168.2 g/ 44 g/mol
Number of moles = 3.82 mol
First, you should convert the temperature unit to absolute temperature.
Second, you shoul graph the points. Then you will find a pretty linear correlations among the points.
You can pick between using the best fit line or you could observe that as you get to higher temperatures the linear behavior is "more perfect".
I found this best fit line:
P = 2.608T + 14
Then, for T = 423K
P = 2.608(423) + 14 = 1117 mmHg
If you prefer to use the last two points, this is the calculus:
[P - P1] / [T - T1] = [P2 - P1] / [T2 - T1]
[P - 960]/[423 -373] = [960 - 880] / [373- 343]
=> P = 1093.3 mmHg.
You can pick any of the results 1177 mmHg or 1093 mmHg, You need more insight to choose one of them: conditions and error of the experiment for example.
Answer:
Standard form: (x+3)^2=1/2(y+3)
f(1) = 29
f(-1) = 5
Explanation:
The standard form of a parabola with a directrix that is horizontal is
(x-h)=4(P)(y-k)
Using the vertex form, find the vertex, foci, and the distance from the vertex to the focus or directrix.
It's easier to use the vertex form to plug in values for x.
f(1) = 2((1)+3)^2-3
f(1) = 29
f(-1) = 2((-1)+3)^2-3
f(-1) = 5
Answer: I2 is the Oxidant; while the 2S2O3(-2) is the reductant.
Explanation:
An Oxidant is any substance that oxidizes, or receives electrons from, another; in so doing, it becomes reduced in oxidation number.
A Reductant thus exactly the opposite.
Note that the equation provided shows that Iodine (I2) received an electron to become NEGATIVELY CHARGED:
I2 --> 2I-.
The oxidation number reduced from 0 to -1.
In contrast, the oxidation number of 2S2O3(-2) increases from -4 to -2.
Thus, I2 is the Oxidant; while the 2S2O3(-2) is the reductant.
